Chapter 6.3, Problem 6.9P

Interpretation Introduction

Interpretation:

The number of moles required to produce ${\text{15 mol of C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}$ glucose.

Concept introduction:

Mole:

A mole is corresponds to the mass of a substance that contains $\text{6}{\text{.023×10}}^{\text{23}}$ particles of the substance.

The mole is the SI units for the amount of a substance and its symbol is mol.

1 mole of carbon -12 has a mass of 12 gram and it contains

$\text{6}{\text{.022140857 x 10}}^{\text{23}}\text{ of carbon atoms}$

The Mole and Avogadro’s number

•For convenience in considering reactions and calculating quantities, chemists think in terms of moles of substances.

•A mole is a quantity of particles defined as Avogadro’s number of particles or formula units of elements or compounds.

•The molecular or formula weight of a compound is the sum of the mass of all atoms in the formula.

•A mole also happens to be 22.4 L of an ideal gas under standard conditions, so 22.4 L of ideal gas represent one gram formula weight of the compound.