Explanation Given information: Consider the horizontal and vertical reaction at A are denoted by A x and A y . Consider the vertical reaction at F is denoted by F y . Assumption: Apply the sign convention for calculating the equations of equilibrium as below. For the horizontal forces equilibrium condition, take the force acting towards right side as positive ( → + ) and the force acting towards left side as negative ( ← − ) . For the vertical forces equilibrium condition, take the upward force as positive ( ↑ + ) and downward force as negative ( ↓ − ) . For moment equilibrium condition, take the clockwise moment as negative and counter clockwise moment as positive. Calculation: Show the free body diagram of frame as shown in Figure 1. Refer to Figure 1. For Equilibrium condition, Consider the sum of the forces in the horizontal direction is zero. Then, ∑ F x = 0 A x + 18 kN = 0 A x = − 18 kN A x = 18 kN ( ← ) Consider the sum of the moment about the point E is zero. Then, ∑ M E = 0 − 18 kN × 4 m − A y × 3.6 m = 0 A y × 3.6 m = − 18 kN × 4 m A y = − 18 kN × 4 m 3.6 m A y = − 20 kN A y = 20 kN ( ↓ ) Thus, the horizontal and vertical reaction at A are A x = 18 kN ( ← ) _ and A y = 20 kN ( ↓ ) _ . Consider the sum of the forces in the vertical direction is zero. Then, ∑ F y = 0 ( A y ) + F y = 0 ( − 20 kN ) + F y = 0 F y = 20 kN ( ↑ ) Show the free body diagram of the member ABC as shown in Figure 2

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Chapter 6.3, Problem 6.79P

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Find the components of the forces acting on member ABC.

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Chapter 6.3, Problem 6.78P

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Chapter 6 Solutions

EBK VECTOR MECHANICS FOR ENGINEERS: STA

Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Prob. 6.2P Ch. 6.1 - Prob. 6.3P Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Using the method of joints, determine the force in...Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Prob. 6.8P Ch. 6.1 - 6.9 and 6.10 Determine the force in each member of...Ch. 6.1 - 6.9 and 6.10 Determine the force in each member of...

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