EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
6th Edition
ISBN: 9781305687875
Author: Gilbert
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Question
Chapter 6.3, Problem 18E
Interpretation Introduction
Interpretation : The order in which the given compounds will elute from the column should be determined.
Concept Introduction :
Normal phase chromatography is used for the separation of polar compounds. Normal phase chromatography uses a polar stationary phase and a nonpolar mobile phase.
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Students have asked these similar questions
A student performed chromatography on a mixture of benzoic acid (C6H5CO₂H),
acetophenone (C6H5C(O)CH3) and styrene (C6H5CHCH₂). She used alumina (Al₂O3)
as the stationary phase and a 9 : 1 mixture of hexane : ethyl ethanoate as the mobile
phase. Rank the order in which the compounds moved, from fastest to slowest.
benzoic acid
acetophenone
styrene
Chromatography involves the separation of two or more compounds/ions caused by their molecular interactions with two phases. True False
One method for the quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is area normalization. Here, complete elution of all the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction involves dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2 and 30.2, in order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78 and 0.88, respectively.
Chapter 6 Solutions
EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
Ch. 6.2 - Prob. 1ECh. 6.2 - Prob. 2ECh. 6.2 - Prob. 3ECh. 6.2 - Prob. 4ECh. 6.2 - Prob. 5ECh. 6.2 - Prob. 6ECh. 6.2 - Prob. 7ECh. 6.2 - Prob. 8ECh. 6.2 - Prob. 9ECh. 6.3 - Prob. 1E
Ch. 6.3 - Prob. 2ECh. 6.3 - Prob. 3ECh. 6.3 - Prob. 4ECh. 6.3 - Prob. 5ECh. 6.3 - Prob. 6ECh. 6.3 - Prob. 7ECh. 6.3 - Prob. 8ECh. 6.3 - Prob. 9ECh. 6.3 - Prob. 10ECh. 6.3 - Prob. 11ECh. 6.3 - Prob. 12ECh. 6.3 - Prob. 13ECh. 6.3 - Prob. 14ECh. 6.3 - Prob. 15ECh. 6.3 - Prob. 16ECh. 6.3 - Prob. 17ECh. 6.3 - Prob. 18ECh. 6.3 - Prob. 19ECh. 6.3 - Prob. 20ECh. 6.4 - Prob. 1ECh. 6.4 - Prob. 2ECh. 6.4 - Prob. 3ECh. 6.4 - Prob. 4ECh. 6.4 - Prob. 5E
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