Chapter 6, Problem 6.7P

(a)

Interpretation Introduction

Interpretation: $6.6\times {10}^{10}\text{J}$ is to be converted in to kilojoules.

Concept Introduction: The SI unit of energy is joule (J). The relationship between joules and kilojoules is given below. $1{\text{kJ=10}}^3\text{J}$

(b)

Interpretation Introduction

Interpretation: $6.6\times {10}^{10}\text{J}$ is to be converted into kilocalories.

Concept Introduction: The calorie (cal) is an older unit defined as the quantity of energy required to raise temperature of 1g of water by $1°\text{C}$ (from $14.5°\text{C}$ to $15.5°\text{C}$ ). The relationship between kilocalories and joules is given below.

  $\begin{array}{c}1\text{cal=4}\text{.184}\text{J}\\ \text{1}{\text{kcal=10}}^3\text{cal}\end{array}$

(c)

Interpretation Introduction

Interpretation: $6.6\times {10}^{10}\text{J}$ is to be converted into British thermal units.

Concept Introduction: The British thermal unit (Btu) is the quantity of energy required to rise the temperature of 1lb of water by $1°\text{F}$ . The relationship between joules and British thermal units is given below:

  $1\text{Btu=1055}\text{J}$