Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained. Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Question

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Answer 1

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

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LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

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Answer 2

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

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Answer 3

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

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Answer 4

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

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Answer 5

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

Answer 6

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

Answer 7

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Answer 8

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Answer 12

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

Answer 13

Ch. 6 - Prob. 6.1P Ch. 6 - An adiabatic process is one that involves no heat...Ch. 6 - Name a common device used to accomplish each...Ch. 6 - Prob. 6.4P Ch. 6 - A system receives 425 J of heat from and delivers...Ch. 6 - A system releases 255 cal of heat to the...Ch. 6 - Prob. 6.7P Ch. 6 - Prob. 6.8P Ch. 6 - The nutritional calorie (Calorie) is equivalent to...Ch. 6 - Classify the following processes as exothermic or...

Answer to Problem 6.1P

Explanation of Solution

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Chapter 6 Solutions