Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained. Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Question

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Answer 1

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

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Answer 2

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

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Answer 3

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

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Answer 4

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

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Answer 5

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

Answer 6

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

Answer 7

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:Whether there is an increase in the internal energy of the body takes place after exercising or not needs to be explained.

Concept introduction: When heat is absorbed by the system and work is done on the system, both q and w is positive. Since internal energy is the sum of work done and the heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

Answer 8

Expert Solution & Answer

Answer to Problem 6.1P

At the time of exercising, heat is discharged from the body (system) and work is done by the body. Therefore, after exercising,the body is warmed because the body loses its energy.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

When heat is absorbed by the system and work is done on the system, both q and w is positive. Since, the internal energy is the sum of work done and heat, it increases under these conditions. On the other hand, if heat is released, work is done by the system, both w and q have negative values resulting decrease in the internal energy.

At the time of exercising, heat is dischargedfrom the body (system) and work is done by the body. Therefore, after exercising, the body is warmed because the body loses its energy.

Answer 12

Conclusion

At the time of exercising, heat is released from the body (system) and work is done by the body. Therefore, after exercising the body is warmed because it loses its energy.

Answer 13

Ch. 6 - Prob. 6.1P Ch. 6 - An adiabatic process is one that involves no heat...Ch. 6 - Name a common device used to accomplish each...Ch. 6 - Prob. 6.4P Ch. 6 - A system receives 425 J of heat from and delivers...Ch. 6 - A system releases 255 cal of heat to the...Ch. 6 - Prob. 6.7P Ch. 6 - Prob. 6.8P Ch. 6 - The nutritional calorie (Calorie) is equivalent to...Ch. 6 - Classify the following processes as exothermic or...

Answer to Problem 6.1P

Explanation of Solution

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Chapter 6 Solutions