Chapter 6, Problem 6.23P

Interpretation Introduction

Interpretation:The value of q when 0.10g of ice is cooled from $10°\text{C}$ to $-75°\text{C}$ needs to be determined.

Concept introduction:The heat can be calculated using temperature change and heat as follows:

  $q=cm\Delta T$

Here q is heat, c is specific heat of the sample, m is mass of the sample and $\Delta \text{T}$ is temperature change in temperature $\left({\text{T}}_{\text{2}}-{\text{T}}_{\text{1}}\right)$ .