Explanation Fluid region: ( 0 < x < L , − h < y < + h ) Eq. (4.50): Φ = μ [ 2 ( ∂ u ∂ x ) 2 + 2 ( ∂ v ∂ y ) 2 + 2 ( ∂ w ∂ z ) 2 + ( ∂ v ∂ x + ∂ u ∂ y ) 2 + ( ∂ w ∂ y + ∂ v ∂ z ) 2 + ( ∂ u ∂ z + ∂ w ∂ x ) 2 ] . Where, viscous dissipation function. Eq. (6.63): V = Q A = h 2 3 μ Δ p L . The velocity profile is parabolic between the plates: u = 1.5 V ( 1 − y 2 h 2 ) . Where, V = h 2 3 μ [ Δ p L ] → Average velocity Let the width of flow is taken as b

8th Edition

ISBN: 9780073398273

Author: Frank M. White

Publisher: McGraw-Hill Education

See similar textbooks

Concept explainers

Fluid Dynamics

The study of the flow of gases and liquids, usually in and around solid surfaces, is known as fluid dynamics in physics and engineering. Fluid dynamics, for example, can be used to evaluate the movement of air through an airplane wing or the surface of a…

Videos

Question

Chapter 6, Problem 6.7CP

To determine

To calculate:

The rate of work done by pressure drop, W˙pressure and compare with the integrated energy dissipated due to viscous function, F.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 6, Problem 6.6CP

Chapter 6, Problem 6.8CP

Students have asked these similar questions

Recall that the CWH equation involves two important assumptions. Let us investigate how these assumptions affect the accuracy of state trajectories under the control inputs optimized in (a) and (b). (c.1): Discuss the assumptions about the chief and deputy orbits that are necessary for deriving CWH.

PROBLEM 2.50 1.8 m The concrete post (E-25 GPa and a = 9.9 x 10°/°C) is reinforced with six steel bars, each of 22-mm diameter (E, = 200 GPa and a, = 11.7 x 10°/°C). Determine the normal stresses induced in the steel and in the concrete by a temperature rise of 35°C. 6c " 0.391 MPa 240 mm 240 mm 6₁ = -9.47 MPa

For some viscoelastic polymers that are subjected to stress relaxation tests, the stress decays with time according to a(t) = a(0) exp(-4) (15.10) where σ(t) and o(0) represent the time-dependent and initial (i.e., time = 0) stresses, respectively, and t and T denote elapsed time and the relaxation time, respectively; T is a time-independent constant characteristic of the material. A specimen of a viscoelastic polymer whose stress relaxation obeys Equation 15.10 was suddenly pulled in tension to a measured strain of 0.5; the stress necessary to maintain this constant strain was measured as a function of time. Determine E (10) for this material if the initial stress level was 3.5 MPa (500 psi), which dropped to 0.5 MPa (70 psi) after 30 s.

Chapter 6 Solutions

Fluid Mechanics

Ch. 6 - Prob. 6.1P Ch. 6 - The present pumping rate of crude oil through the...Ch. 6 - The Keystone Pipeline in the chapter opener photo...Ch. 6 - For flow of SAE 30 oil through a 5-cm-diameter...Ch. 6 - In flow past a body or wall, early transition to...Ch. 6 - P6.6 For flow of a uniform stream parallel to a...Ch. 6 - SAE 10W30 oil at 20°C flows from a tank into a...Ch. 6 - P6.8 When water at 20°C is in steady turbulent...Ch. 6 - A light liquid 950kg/m3 flows at an average...Ch. 6 - Water at 20°C flows through an inclined...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The rate of work done by pressure drop, W ˙ p r e s s u r e and compare with the integrated energy dissipated due to viscous function, F.

Concept explainers

Videos

To calculate: The rate of work done by pressure drop, W˙pressure and compare with the integrated energy dissipated due to viscous function, F.

Want to see the full answer?

Chapter 6 Solutions

To calculate:

The rate of work done by pressure drop, W˙pressure and compare with the integrated energy dissipated due to viscous function, F.