Explanation Given information: The fluid is crude oil at 40 ° C Pipe diameter is equal to 36 i n Flow rate is equal to 590000 barrels per day Pipe is made of new steel The power of the pump can be defined as below, P o w e r = ρ g Q h f In above equation, ρ - Density of the fluid Q - Volumetric flow rate h p - Head loss The head loss is defined as, h f = V 2 2 g ( f L D ) In above equation, V - Velocity of the flow f - Friction factor L - Length D - Diameter The Reynolds’s number is defined as, Re = ρ V D μ Assume, that the crude oil at 40 ° C will have, ρ = 1.67 s l u g / f t 3 μ = 1.11 × 10 − 4 s l u g / ( f t . s ) The friction factor is defined as, 1 f 1 2 = 2.0 log ( Re f 1 2 ) − 0.8 Calculation: Convert, Q = 590000 b a r r e l s / d a y = 38.35 f t 3 / s Calculate the velocity, Q = V A 38.35 f t 3 / s = V ( π 4 ( 36 12 f t ) 2 ) V = 5.425 f t / s Calculate the Reynolds’s number, Re = ρ V D μ = ( 1.67 s l u g / f t 3 ) ( 5.425 f t / s ) ( 3 f t ) μ = 1.11 × 10 − 4 s l u g / f t

8th Edition

ISBN: 9780073398273

Author: Frank M. White

Publisher: McGraw-Hill Education

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Question

Chapter 6, Problem 6.46P

To determine

The pump horsepower required per pump of a mile.

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Chapter 6, Problem 6.45P

Chapter 6, Problem 6.47P

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Chapter 6 Solutions

Fluid Mechanics

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