Explanation Given Information: With the volume rate Q, the fluid flows through the horizontal pipe that is larger with the diameter of 25 mm and then gets divided into two small pipes. The flow inside the larger pipe is three times the smaller pipe. The energy loss due to friction in the pipe is given as: h f = ( z 2 − z 1 ) + ( Δ P ρ g ) When substituting ( z 2 − z 1 ) = 0 we get: h f = ( Δ P ρ g ) The flow rate when it is laminar is given as, Q = π ρ g d 4 h f 128 μ L Were, d = diameter ρ = density V = velocity μ = viscosity Therefore we have, Q = π ρ g d 4 128

8th Edition

ISBN: 9780073398273

Author: Frank M. White

Publisher: McGraw-Hill Education

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Chapter 6, Problem 6.16P

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The diameter of the smaller pipe when the flow is laminar.

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