Interpretation:
The products of the given reactions have to be determined and if the products can exist as stereoisomers, then those have to be shown.
Concept Introduction:
Addition Reaction: It is defined as
Electrophilic addition: It is a type of addition reaction in which the pi bond present in the molecule breaks as the electrophile approaches and results in the formation of product with sigma bond.
Acid Catalyzed Hydration Reaction: The reaction involves breaking of phi bonds between carbon-carbon multiple bonds and addition of alcohol to more substituted position of carbon in the molecule.
First step is the acid donates proton to the alkene which leads to the formation of more stable carbo cation.
Then, the water is added to the given alkene through acid catalyzed reaction where the water gets added to the carbo cation finally, the removal of one proton from oxonium ion (oxygen with one positive charge) using water results in the formation of product.
Halogen addition to an alkene:
The addition reaction of halides to
Mainly
In general, the reaction can be shown as below.
When the bromine approaches the alkene, one bromine accepts the electrons from alkene and give them to the other bromine and a cyclic bromonium ion intermediate is formed.
The formed unstable intermediate reacts with
Lindlar reduction: The alkenes or
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Chapter 6 Solutions
EBK ESSENTIAL ORGANIC CHEMISTRY
- Do the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forwardNonearrow_forward
- Redraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forward
- Add curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Draw curved arrows. : 0: si H : OH :: H―0: Harrow_forwardConsider this step in a radical reaction: Br N O hv What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. O primary Otermination O initialization O electrophilic O none of the above × ☑arrow_forwardNonearrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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