Range of gain K for the given system to be stable. P ( s ) = T ( s ) Q ( s ) = 1 × 10 − 6 s 2 + 1.314 × 10 − 9 s + 2.66 × 10 − 13 ( s 3 + 0.00163 s 2 + 5.272 × 10 − 7 s + 3.538 × 10 − 11 )

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Chapter 6, Problem 58P

To determine

Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

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3- Find the optimum of y = 9x - 0.1x ^ 2 in the interval 0 <= x <= 100 and alpha = 0.05 Use two and three experiments sequential search methods?

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2- Find the optimum minimum point of y = x²-6x + 2 in the interval 0 ≤ x ≤ 10 using sequential search method with three experiments. the accuracy a = 0.06. 3- Find the optimum of y = 9x -0.1 x² in the interval 0 ≤ x ≤ 100, and α = 0.05 Use two and three experiments sequential search methods?

Answer 2

Question

Chapter 6, Problem 58P

To determine

Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

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Answer 3

Question

Chapter 6, Problem 58P

To determine

Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

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Answer 4

Question

Chapter 6, Problem 58P

To determine

Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

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Answer 5

Chapter 6, Problem 58P

To determine

Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

Answer 6

Chapter 6, Problem 58P

To determine

Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

Answer 7

Chapter 6, Problem 58P

To determine

Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

Answer 8

Expert Solution & Answer

Answer 9

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Answer 10

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Answer 11

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Range of gain K for the given system to be stable. P ( s ) = T ( s ) Q ( s ) = 1 × 10 − 6 s 2 + 1.314 × 10 − 9 s + 2.66 × 10 − 13 ( s 3 + 0.00163 s 2 + 5.272 × 10 − 7 s + 3.538 × 10 − 11 )

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Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

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Chapter 6 Solutions

Range of gain K for the given system to be stable. P ( s ) = T ( s ) Q ( s ) = 1 × 10 − 6 s 2 + 1.314 × 10 − 9 s + 2.66 × 10 − 13 ( s 3 + 0.00163 s 2 + 5.272 × 10 − 7 s + 3.538 × 10 − 11 )

Concept explainers

Videos

Range of gain K for the given system to be stable. P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)

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Chapter 6 Solutions

Range of gain K for the given system to be stable.

P(s)=T(s)Q(s)=1×10−6s2+1.314×10−9s+2.66×10−13(s3+0.00163s2+5.272×10−7s+3.538×10−11)