Concept explainers
A)
“for” loop:
A control loop that repeats for a particular number of iterations is termed as a “count-controlled loop”; C++ provide such type of loop known as the “for” loop.
The “for” loop is used to perform an exact number of iterations and it contains three elements. They are as follows:
- Initialization
- Condition
- Increment/Decrement
- The initialization part is executed once at the beginning. The condition is then executed.
- When the condition result is false, the loop fails.
- When the condition result is true, the loop is executed and the increment/decrement operator is evaluated.
- The condition is executed until the loop gets terminated.
Syntax:
for (initialization; condition; update)
{
Statement1;
Statement2;
.
.
}
B)
“for” loop:
A control loop that repeats for a particular number of iterations is termed as a “count-controlled loop”; C++ provide such type of loop known as the “for” loop.
The “for” loop is used to perform an exact number of iterations and it contains three elements. They are as follows:
- Initialization
- Condition
- Increment/Decrement
- The initialization part is executed once at the beginning. The condition is then executed.
- When the condition result is false, the loop fails.
- When the condition result is true, the loop is executed and the increment/decrement operator is evaluated.
- The condition is executed until the loop gets terminated.
Syntax:
for (initialization; condition; update)
{
Statement1;
Statement2;
.
.
}
C)
“for” loop:
A control loop that repeats for a particular number of iterations is termed as a “count-controlled loop”; C++ provide such type of loop known as the “for” loop.
The “for” loop is used to perform an exact number of iterations and it contains three elements. They are as follows:
- Initialization
- Condition
- Increment/Decrement
- The initialization part is executed once at the beginning. The condition is then executed.
- When the condition result is false, the loop fails.
- When the condition result is true, the loop is executed and the increment/decrement operator is evaluated.
- The condition is executed until the loop gets terminated.
Syntax:
for (initialization; condition; update)
{
Statement1;
Statement2;
.
.
}
Want to see the full answer?
Check out a sample textbook solutionChapter 5 Solutions
Starting Out with C++: Early Objects
- #include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…arrow_forwardbe recor #include #include minutes #include limit on int func(int, int, int, int); main(){ srand(time(NULL)); int a, b, c, fNum; printf("Choose three different numbers between 0-39:"); scanf ("%d%d%d", &a, &b, &c); fNum = func (a, b, c, 25); printf("\nThe result: %d", fNum); } int func (int ul, int u2, int u3, int iter){ srand (time (NULL)); int n1=0, i=0, count=0; for (;iarrow_forwardC++ programming Chapter(s) Covered: Chapter 1-8 Concepts tested by the program: Working with one dimensional parallel arrays Use of functions Use of loops and conditional statements Project Description The Lo Shu Magic Square is a grid with 3 rows and 3 columnsshown below. The Lo Shu Magic Square has the following properties: The grid contains the numbers 1 – 9 exactly. Each number 1 – 9must not be used more than once. So, if you were to add up thenumbers used, The sum of each row, each column and each diagonal all add upto the same number, Write a program that simulates a magic square using 3 onedimensional parallel arrays of integer type. Each one the arrays corresponds to a row of the magicsquare. The program asks the user to enter the values of the magicsquare row by row and informs the user if the grid is a magicsquare or not. See the sample outputs for more clarification. Project Specifications Input for this project: Values of the grid (row by row) Output for this…arrow_forwardDetermine all the output from the following program as it would appear on the screen. void func1(int); void func2(int = 4, int = 5, int = 2); int func3(int &, int, int); %3D int main() { int x = 0, z = 0, y = 2; func1(y); cout << y << endl; func2(x, y, z); func2(); func3(x, y, z); = Z func1(x); cout << x << " " << y << " " << z << endl; return 0; } void func1(int b) { static int a;arrow_forward#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05); cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…arrow_forward#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…arrow_forward#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…arrow_forwardint x1 = 66; int y1 = 39; int d; _asm { } mov EAX, X1; mov EBX, y1; push EAX; push EBX; pop ECX mov d, ECX; What is d in decimal format?arrow_forwardC++arrow_forwardDart game: Dart location Write a function called DartNumbers() that takes the location of darts thrown as an input, and finds the number of darts that hit the regions yellow, red, blue, and green. A 20x20 square dart board, as shown in the image below, consists of concentric circles with the center at (0,0). The radius of the yellow circle is 3, the red circle is 5, and the blue circle is 10. A dart player throws 10 darts at the board randomly such that any place on the board can be hit with an equal chance. The rand() function can be used to obtain a number with uniform distribution between -10 and 10. Uniform distribution with a given interval means that an equal probability exists to get a number in that interval. Dart Board 10 2. -2 -10 -10 -2 4. 8. 10 The inputs of the function DartNumbers() are: throwX: Indicates the x positions of the darts on the board. throwX is a 1x10 array of random numbers between -10 and 10 with a uniform distribution using the rand function. throw Y:…arrow_forwardEach of the following definitions and program segments has errors. Locate as many as you can and correct the errors. a) void showValues (int nums) { for (int i = 0; i<8; i++) cout<arrow_forwardC++ beginnerarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_iosRecommended textbooks for you
- Database System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill EducationStarting Out with Python (4th Edition)Computer ScienceISBN:9780134444321Author:Tony GaddisPublisher:PEARSONDigital Fundamentals (11th Edition)Computer ScienceISBN:9780132737968Author:Thomas L. FloydPublisher:PEARSON
- C How to Program (8th Edition)Computer ScienceISBN:9780133976892Author:Paul J. Deitel, Harvey DeitelPublisher:PEARSONDatabase Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781337627900Author:Carlos Coronel, Steven MorrisPublisher:Cengage LearningProgrammable Logic ControllersComputer ScienceISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
Database System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill EducationStarting Out with Python (4th Edition)Computer ScienceISBN:9780134444321Author:Tony GaddisPublisher:PEARSONDigital Fundamentals (11th Edition)Computer ScienceISBN:9780132737968Author:Thomas L. FloydPublisher:PEARSONC How to Program (8th Edition)Computer ScienceISBN:9780133976892Author:Paul J. Deitel, Harvey DeitelPublisher:PEARSONDatabase Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781337627900Author:Carlos Coronel, Steven MorrisPublisher:Cengage LearningProgrammable Logic ControllersComputer ScienceISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education