
Starting Out with C++: Early Objects
8th Edition
ISBN: 9780133360929
Author: Tony Gaddis, Judy Walters, Godfrey Muganda
Publisher: Addison-Wesley
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Expert Solution & Answer
Chapter 5, Problem 41RQE
Explanation of Solution
Purpose of the given code:
The purpose of the give code segment is to print the value of “count” using “for” loop.
Program:
The given code segment is highlighted below.
// Include required header files
#include <iostream> // Line 1
using namespace std; // Line 2
// Main function
int main() // Line 3
{ // Line 4
// Loop from 1 through 10
for(int count = 1; count <= 10; count++) // Line 5
{ // Line 6
//Print the value
cout << ++count << " "; // Line 7
} // Line 8
// Return value
return 0; // Line 9
} // Line 10
Explanation:
- Include required header files on “Line 1” and “Line 2”.
- Define a function “main ()” on “Line 3”. Inside this function,
- “Line 5” loops from “1” through “10” using “for” loop.
- “Line 7” pre-increments “count” variable and it is printed.
- “Line 9” returns the statement.
- “Line 5” loops from “1” through “10” using “for” loop.
Explanation of “for” loop:
- Consider the value of the variable “count = 1”
- “1” is less than “10”...
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using r language
I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
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Chapter 5 Solutions
Starting Out with C++: Early Objects
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