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Concept explainers
Interpretation:
The parent chain has to be chosen and numbered correctly for the given compound.
Concept Introduction:
All the molecules have their unique names. These names must be known in order to communicate. But remembering all the chemical names is impossible as there are many numbers of molecules. To avoid this, the
Stereoisomerism | Substituents | Parent | Unsaturation | Functional Group |
Stereoisomerism indicate if the considered molecule has any stereocenters are present (R,S) and if double bond is present are cis/trans. In order to name a double bond as cis/trans, the important condition is that, an identical group has to be present on either side of the double bond. If the identical groups are present on the same side of double bond, then it is known as cis. If the identical groups are present on the opposite side of the double bond then it is known as trans.
The groups that are connected to the main carbon chain is known as substituents. The substituents are identified after the carbon chain is identified and the functional group present in the given compound also identified. The substituents are named by adding “yl” to the end of the name which indicate that it is a substituent is an alkyl. The
The longest carbon chain is known as the parent. Parent carbon chain is the lengthiest carbon chain in the molecule that must include the functional group that is present in the compound. The longest carbon chain is identified and the parent name is given by the number of carbon atoms that is present in it. It must be remembered that even though functional group is not present in parent carbon chain, the double bond, triple bond if present has to be included. Numbering becomes a part of all the parts in IUPAC name. After identifying the parent chain, the numbering is done. If functional group is present in the given compound, the numbering is given in such a way that the functional group gets the least number. Then the double bond, triple bond.
Number of carbon atoms in chain | Parent |
1 | Meth |
2 | Eth |
3 | Prop |
4 | But |
5 | Pent |
6 | Hex |
Unsaturation indicates that if any triple or double bonds are present in the molecule. If a compound contains a double bond it is named as “-en-” and if a triple bond is present “-yn-” is used. If a compound contains two double bonds, then it is named as “-dien-”. If three double bonds are present in the given compound, then it is named as “-trien-”. This same rule applies for the compound that contains multiple triple bonds also.
Functional group is the one after which the considered compound is being named.
Functional Group | Class of compound | Suffix |
![]() | Ester | -oate |
![]() | Ketone | -one |
![]() | Aldehyde | -al |
![]() | -oic acid | |
![]() | Alcohol | -ol |
![]() | -amine |
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Chapter 5 Solutions
Organic Chemistry As a Second Language: First Semester Topics
- X Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forwardNonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forward
- Nonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forwardDo the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forward
- Predict and draw the product of the following organic reaction:arrow_forwardNonearrow_forwardRedraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forward
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