Chapter 5, Problem 98P

When a system is subjected to a linear rigid body motion with constant linear acceleration a along a distance L, the modified Bernoulli Equation takes the form

   $\left(\frac{P_1}{\rho }+\frac{V_1^2}{2}+g{z}_1\right)-\left(\frac{P_2}{\rho }+\frac{V_2^2}{2}+gz\right)=aL+\text{Losses}$

where $V_1$ and $V_2$ , are velocities relative to a fixed point and Losses’ which represents frictional losses is zero when the frictional effects are negligible. The tank with two discharge pipes shown in Fig. P5−98 accelerates to the left at a constant linear acceleration of 3 ${\text{m/s}}^2$ . If volumetric flow rates from both pipes are to be identical, determine the diameter D of the inclined pipe. Disregard any frictional effects.

FIGURE P5−98