The demand for electric power is usually much higher during the day than it is at night. and utility companies often sell power at night at much lower prices to encourage consumers to use the available power generation capacity and to avoid building new expensive power plants that will be used only a short time during peak periods. Utilities are also willing to purchase power produced during the day from private parties at a high price. Suppose a utility company is selling electric power for $0.06/kWh at night and is willing to pay $0.1 3/1Wh for power produced during the day. To take advantage of this opportunity, an entrepreneur is considering building a large reservoir 50 in above the lake level, pumping water from the lake to the reservoir at night using cheap power. and letting the water flow from the reservoir back to the lake during the day, producing power as the pump-motor operates as a turbine- generator during reverse flow. Preliminary analysis shows that a water flow rate of 2 m 3 /s can be used in either direction, and the irreversible head loss of the piping system is 4 in. The combined pump--motor and turbine-generator efficiencies are expected to be 75 percent each. Assuming the system operates for 10 h each in the pump and turbine modes during a typical day, determine the potential revenue this pump-turbine system can generate per year.
The demand for electric power is usually much higher during the day than it is at night. and utility companies often sell power at night at much lower prices to encourage consumers to use the available power generation capacity and to avoid building new expensive power plants that will be used only a short time during peak periods. Utilities are also willing to purchase power produced during the day from private parties at a high price. Suppose a utility company is selling electric power for $0.06/kWh at night and is willing to pay $0.1 3/1Wh for power produced during the day. To take advantage of this opportunity, an entrepreneur is considering building a large reservoir 50 in above the lake level, pumping water from the lake to the reservoir at night using cheap power. and letting the water flow from the reservoir back to the lake during the day, producing power as the pump-motor operates as a turbine- generator during reverse flow. Preliminary analysis shows that a water flow rate of 2 m 3 /s can be used in either direction, and the irreversible head loss of the piping system is 4 in. The combined pump--motor and turbine-generator efficiencies are expected to be 75 percent each. Assuming the system operates for 10 h each in the pump and turbine modes during a typical day, determine the potential revenue this pump-turbine system can generate per year.
The demand for electric power is usually much higher during the day than it is at night. and utility companies often sell power at night at much lower prices to encourage consumers to use the available power generation capacity and to avoid building new expensive power plants that will be used only a short time during peak periods. Utilities are also willing to purchase power produced during the day from private parties at a high price.
Suppose a utility company is selling electric power for $0.06/kWh at night and is willing to pay $0.1 3/1Wh for power produced during the day. To take advantage of this opportunity, an entrepreneur is considering building a large reservoir 50 in above the lake level, pumping water from the lake to the reservoir at night using cheap power. and letting the water flow from the reservoir back to the lake during the day, producing power as the pump-motor operates as a turbine- generator during reverse flow. Preliminary analysis shows that a water flow rate of 2 m3/s can be used in either direction, and the irreversible head loss of the piping system is 4 in. The combined pump--motor and turbine-generator efficiencies are expected to be 75 percent each. Assuming the system operates for 10 h each in the pump and turbine modes during a typical day, determine the potential revenue this pump-turbine system can generate per year.
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A torque wrench is used to tighten the pipe shown.Dimensions: S1 = 400 mm; S2 = 250 mm; S3 = 100 mmModulus of Rigidity G = 78 GPa1. The diameter of the solid pipe is 20 mm. How much is themaximum force P (N) that can be applied based on theallowable shear stress of 60 MPa?2. For a hollow pipe with 50 mm outside diameter and is 6 mmthick, compute for the maximum force P (kN) that can beapplied such that the angle of twist at A does not exceed 5degrees.3. The torque applied to tighten the hollow pipe is 200 N-m.Given: Pipe outside diameter = 50 mm Pipe thickness = 6 mmSolve for the resulting maximum shear stress (MPa) in the pipe.
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6: The shaft carries a total torque T0 that is uniformly distributedover its length L. Determine the angle of twist (degrees) of the shaft in termsif T0 = 1.2 kN-m, L = 2 m, G = 80 GPa, and diameter = 120 mm.
2. Calculate the force in all members of the trusses shown using the method of joints.
A
5525 lb
C
3500 lb
BY
14'-0"
D
10'- 0"
6250 lb
10'- 0"
E
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