Chapter 5, Problem 5.50AP

Interpretation Introduction

(a)

Interpretation:

The product obtained by the free-radical reaction of ${\text{H}}_{\text{2}}\text{C}={\text{CH}}_{\text{2}}$, ${\left({\text{CH}}_{\text{3}}\right)}_2\text{C}={\text{CH}}_{\text{2}}$ and ${\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{C}={\text{CHCH}}_{\text{3}}$ with methyl radical is to be drawn.

Concept introduction:

A hydrocarbon in which carbon atom is bonded to another carbon atom through double bond $\left(-\text{C}=\text{C}-\right)$ is known as alkene. The double bond between carbon atoms is made up of one $\sigma$ and one $\pi$ bond.

Interpretation Introduction

(b)

Interpretation:

The order of relative rates of ${\text{H}}_{\text{2}}\text{C}={\text{CH}}_{\text{2}}$, ${\left({\text{CH}}_{\text{3}}\right)}_2\text{C}={\text{CH}}_{\text{2}}$ and ${\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{C}={\text{CHCH}}_{\text{3}}$ is to be explained.

Concept introduction:

A hydrocarbon in which carbon atom is bonded to another carbon atom through double bond $\left(-\text{C}=\text{C}-\right)$ is known as alkene. The double bond between carbon atoms is made up of one $\sigma$ and one $\pi$ bond.