Concept explainers
(a)
Interpretation:
The
Concept introduction:
The
(b)
Interpretation:
The
Concept introduction:
The bond dissociation energy is denoted by
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Organic Chemistry
- 2 HC= CH + 5 O2 > 4 co2 + 2 h2o What is the energy of the reaction and is it exo- or endothermic?arrow_forwardWhich is the strongest bond energy? Cl(g) ΔH°f, = +121.3 kJ mol–1 CCl4(g) ΔH°f, = –95.98 kJ mol–1 HCl(g) ΔH°f, = –92.3 kJ mol–1 Question 8 options: Cl–Cl in Cl2 H–Cl in HCl C–Cl in CCl4arrow_forwardHow do I (a) determine the energy change in the following reaction2 O2 + CH4→ CO2 + 2 H2Ogiven the following bond dissociation energies:C-C 340kJ/mol; C-H 420kJ/mol; O=O 490 kJ/mol; O-H 460 kJ/mol; C=O 720 kJ/mol. (b) Is the reaction exothermic or endothermic? Explaination?arrow_forward
- Use the indicated average bond enthalpies to estimate the change in enthalpy, ΔHo, for the reaction between methane and iodine to produce iodomethane and hydrogen iodide: CH4(g) + I2(g) → CH3I(g) + HI(g) ΔHo = ? It may be helpful to draw the Lewis electron dot structure for each reactant and product; all reactants and products have single bonds. average bond enthalpies (kJ) C - H 413 , C - I 240 , H - I 299 , I - I 151 Express your answer in units of kilojoules, but do not include the units on your submitted answer.arrow_forwardCalculate the enthalpy change (ΔH) for the reaction H2 + I2 → 2 HI,given the following bond dissociation energies: BE(H – H) = 436.4 kJ BE(I – I) = 151.0 kJ BE(H – I) = 298.3 kJarrow_forwardFor each of the following covalent bonds: (a) use the symbols δ+ and δ- to indicate the direction of polarity (if any).(a) C-F; (b) N-Br; (c) B-C; (d) Si-H(b) Rank the following covalent bonds in order of increasing polarity. (i) C-H, O-H, N-H; (ii) C-N, C-O, B-O; (iii) C-P, C-S, C-Narrow_forward
- Use the given bond dissociation energies to approximate the enthalpy change for the reaction of methane with molecular chlorine as shown in the reaction below. CH4(g) + 3Cl2₂(g) → CHCl3(g) + 3HCl(g) I BDE: C-H = 410 kJ/mol C-CI 330 kJ/mol a) -227 kJ b) -327 kJ c) -457 kJ d) +227 kJ e) + 327 kJ CI-CI = 243 kJ/mol H-CI = 432 kJ/mol H-H = 436 kJ/mol C-C= 350 kJ/molarrow_forwardCalculate the enthalpy change for the following reactions using the bond enthalpy given below. (Bond enthalpy/kJ : H−H = 436, C−H = 413, C=O = 799, O=O = 495, O−H = 463) (a) H2(g) + 1⁄2O2(g) → H2O(g) (b) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)arrow_forwardThe structural formula for ethane is (a) What is the molecular formula for ethane?(b) What is its empirical formula?(c) Can we infer from this drawing that the H—C—H bond angles are 90 degrees?arrow_forward
- (a) Draw a Lewis diagram for carbonic acid, H,CO3, with a central carbon atóm bonded to the three oxygen atoms. (b) Carbonic acid is unstable in aqueous solution and converts to dissolved carbon dioxide. Use bond enthal- pies to estimate the enthalpy change for the following reaction: H,CO;→ H,O + CO,arrow_forwardCovalent bonds: H―HC―HO―HO═O C≡O Bond energy (kJ/mol):4364154654981080Calculate the enthalpy change (H, in kJ/mol) for the following reaction and indicate whether the reaction is exothermic or endothermic.(*BE for C═Oin CO2)(a) CH4(g)+ H2O(g)CO(g)+ 3H2(g);arrow_forwardI need this solution, Calculate the Enthalpy Change (ΔH) from average bond energies, which have been listed below in KJ/mol, for the following reaction and identify the nature of the reaction: CH3COOH + CH3OH → CH3COOCH3 + H2O [C‒H: 413; C‒C: 347; C=O: 745; C=C: 614; Cl‒Cl: 239, C‒O: 358; O‒H: 467arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning