Chapter 5, Problem 5.36QP

(a)

Interpretation Introduction

Interpretation:

Three flasks of $\text{25}\text{.0 L}$ volume namely $\text{1}\text{.0 atm}$ of $\text{He}$ gas, $\text{1}\text{.5 atm}$ of $\text{Xe}$ gas and $\text{2}\text{.0 atm}$ of ${\text{F}}_{\text{2}}$ gas are placed on the shelf in a chemistry stock room

The flask with greater number of moles of gas has to be identified.

Concept Introduction:

Ideal Gas Law:

The ideal gas equation is:

$\text{PV = nRT}$

Where,

P is the pressure

V is the volume

T is the temperature

R is molar gas constant

n is the mole

(b)

Interpretation Introduction

Interpretation:

Three flasks of $\text{25}\text{.0 L}$ volume namely $\text{1}\text{.0 atm}$ of $\text{He}$ gas, $\text{1}\text{.5 atm}$ of $\text{Xe}$ gas and $\text{2}\text{.0 atm}$ of ${\text{F}}_{\text{2}}$ gas are placed on the shelf in a chemistry stock room

The general changes that can be done to keep the other two container at same pressure of $\text{He}$ gas should be explained.

Concept Introduction:

The ideal gas equation is:

$\text{PV = nRT}$

Where,

P is the pressure

V is the volume

T is the temperature

R is molar gas constant

n is the mole