Chapter 5.7, Problem 5.14E

Interpretation Introduction

Interpretation:

The time taken for $\text{10}\text{.0 mL}$ of oxygen, ${\text{O}}_{\text{2}}$ to effuse from the given container at the given temperature and pressure has to be calculated

Concept Introduction:

Graham’s law of effusion:

Graham’s law of effusion states that “at constant temperature and pressure, the rate of effusion of gas molecule from a particular hole is inversely proportional to the square root  of the molecular weight of the gas” and is given as,

$\text{Rate of effusion of molecules }\propto \frac{\text{1}}{\sqrt{{\text{M}}_{\text{m}}}}$

Where,

${\text{M}}_{\text{m}}$ is the molar mass of the gas