The partial pressure of each of the gases in the undersea habitat which is 58.5 m below the sea level with the pressure of 6.91 atm has to be calculated Concept Introduction: Partial Pressure: Dalton’s law of partial pressure states that “the total pressure (P) of the mixture is equal to the sum of the partial pressures (P A , P B , P C ..... ) of all the component gases (A, B, C ...... ) present in the mixture” and is given as, P = P A + P B + P C + ....... The ideal gas law for the individual gas component A is given as, P A V = n A RT Mole fraction: Mole fraction of a component gas is defined as “the fraction of moles of that component in the total moles of gas mixture” and is given as, Mole fraction of A = n A n = P A P
The partial pressure of each of the gases in the undersea habitat which is 58.5 m below the sea level with the pressure of 6.91 atm has to be calculated Concept Introduction: Partial Pressure: Dalton’s law of partial pressure states that “the total pressure (P) of the mixture is equal to the sum of the partial pressures (P A , P B , P C ..... ) of all the component gases (A, B, C ...... ) present in the mixture” and is given as, P = P A + P B + P C + ....... The ideal gas law for the individual gas component A is given as, P A V = n A RT Mole fraction: Mole fraction of a component gas is defined as “the fraction of moles of that component in the total moles of gas mixture” and is given as, Mole fraction of A = n A n = P A P
Solution Summary: The author explains that the partial pressure of each of the gases in the undersea habitat, which is 58.5 m below the sea level, has to be calculated.
Study of body parts and their functions. In this combined field of study, anatomy refers to studying the body structure of organisms, whereas physiology refers to their function.
Chapter 5, Problem 5.86QP
Interpretation Introduction
Interpretation:
The partial pressure of each of the gases in the undersea habitat which is 58.5 m below the sea level with the pressure of 6.91 atm has to be calculated
Concept Introduction:
Partial Pressure:
Dalton’s law of partial pressure states that “the total pressure (P) of the mixture is equal to the sum of the partial pressures(PA, PB, PC.....) of all the component gases(A, B, C......) present in the mixture” and is given as,
P = PA + PB + PC + .......
The ideal gas law for the individual gas component A is given as,
PAV = nART
Mole fraction:
Mole fraction of a component gas is defined as “the fraction of moles of that component in the total moles of gas mixture” and is given as,
Arrange the solutions in order of increasing acidity. (Note that K (HF) = 6.8 x 10 and K (NH3) = 1.8 × 10-5)
Rank solutions from least acidity to greatest acidity. To rank items as equivalent, overlap them.
▸ View Available Hint(s)
Least acidity
NH&F NaBr NaOH
NH,Br NaCIO
Reset
Greatest acidity
1. Consider the following molecular-level diagrams of a titration.
O-HA molecule
-Aion
°°
о
°
(a)
о
(b)
(c)
(d)
a. Which diagram best illustrates the microscopic representation for the
EQUIVALENCE POINT in a titration of a weak acid (HA) with sodium.
hydroxide?
(e)
Answers to the remaining 6 questions will be hand-drawn on paper and submitted as a single
file upload below:
Review of this week's reaction:
H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O --->
H₂NC(=NH)N(CH3)CH2COOH (creatine)
Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing
the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts)
Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts)
Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3
pts)
NH2(C=NH)-N(CH)CH2COOH
This bond
Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem
Q9 is valid). (4 pts)
Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should
be ready to understand the first half of one of the Grignard reactions presented in a past…
Chapter 5 Solutions
OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)
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