The factor of volume of air got increased when it is taken from earth’s surface to the stratosphere has to be calculated Concept Introduction: Combined Gas Law : Boyle’s law: V α 1 P (at constant T) P f V f = P i V i (at constant T) Charles’s law: V α T (at constant P) V f T f = V i T i (at constant P) The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)” V α T P For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as P f V f T f = P i V i T i On rearranging, we get V f = V i × P i P f × T f T i Where, T i a n d T f are initial temperature and final temperature respectively V i a n d V f are initial volume and final volume respectively P i a n d P f are initial pressure and final pressure respectively
The factor of volume of air got increased when it is taken from earth’s surface to the stratosphere has to be calculated Concept Introduction: Combined Gas Law : Boyle’s law: V α 1 P (at constant T) P f V f = P i V i (at constant T) Charles’s law: V α T (at constant P) V f T f = V i T i (at constant P) The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)” V α T P For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as P f V f T f = P i V i T i On rearranging, we get V f = V i × P i P f × T f T i Where, T i a n d T f are initial temperature and final temperature respectively V i a n d V f are initial volume and final volume respectively P i a n d P f are initial pressure and final pressure respectively
Solution Summary: The author explains that the factor of volume of air got increased when it is taken from earth’s surface to the stratosphere has to be calculated.
Study of body parts and their functions. In this combined field of study, anatomy refers to studying the body structure of organisms, whereas physiology refers to their function.
Chapter 5, Problem 5.110QP
Interpretation Introduction
Interpretation:
The factor of volume of air got increased when it is taken from earth’s surface to the stratosphere has to be calculated
Concept Introduction:
Combined Gas Law:
Boyle’s law:
Vα1P (at constant T)
PfVf=PiVi (at constant T)
Charles’s law:
Vα T (at constant P)
VfTf=ViTi (at constant P)
The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)”
VαTP
For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as
PfVfTf=PiViTi
On rearranging, we get
Vf=Vi×PiPf×TfTi
Where,
Tiand Tf are initial temperature and final temperature respectively
Viand Vf are initial volume and final volume respectively
Piand Pf are initial pressure and final pressure respectively
Lab Data
The distance entered is out of the expected range.
Check your calculations and conversion factors.
Verify your distance. Will the gas cloud be closer to the cotton ball with HCI or NH3?
Did you report your data to the correct number of significant figures?
- X
Experimental Set-up
HCI-NH3
NH3-HCI
Longer Tube
Time elapsed (min)
5 (exact)
5 (exact)
Distance between cotton balls (cm)
24.30
24.40
Distance to cloud (cm)
9.70
14.16
Distance traveled by HCI (cm)
9.70
9.80
Distance traveled by NH3 (cm)
14.60
14.50
Diffusion rate of HCI (cm/hr)
116
118
Diffusion rate of NH3 (cm/hr)
175.2
175.2
How to measure distance and calculate rate
For the titration of a divalent metal ion (M2+) with EDTA, the stoichiometry of the reaction is typically:
1:1 (one mole of EDTA per mole of metal ion)
2:1 (two moles of EDTA per mole of metal ion)
1:2 (one mole of EDTA per two moles of metal ion)
None of the above
Please help me solve this reaction.
Chapter 5 Solutions
OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell