Chapter 5, Problem 5.93QP

Interpretation Introduction

Interpretation:

The temperature at which the ${\text{CO}}_{\text{2}}$ molecule have the rms speed equal to that of ${\text{H}}_{\text{2}}$ molecules at $25^{o}C$ has to be calculated

Concept Introduction:

Root-mean-square (rms):

The root-mean-square molecular speed (u) is given by the below formula.

$\begin{array}{l}u\text{=}\sqrt{\frac{3\text{RT}}{{\text{M}}_{\text{m}}}}\\ ={\left(\frac{3\text{RT}}{{\text{M}}_{\text{m}}}\right)}^{\frac{1}{2}}\end{array}$

Where,

R is the molar gas constant

T is the absolute temperature

${\text{M}}_{\text{m}}$ is the molar mass of the gas