Chapter 5.2, Problem 5.2CC

(a)

Interpretation Introduction

Interpretation:

The change of pressure by decreasing the temperature by ${10}^{\circ }\text{C}$ and then increasing the volume in a 10.0 L flask containing ${\text{H}}_{\text{2}}$ gas at 20 atm has to be explained and compared with the starting pressure.

Concept Introduction:

Boyle’s law:

$\text{ V}\alpha \frac{1}{\text{P}}\text{ (at constant T)}$

$P_f{V}_f=P_i{\text{V}}_i\text{ (at constant T)}$

Charles’s law:

$\text{ V}\alpha \text{ T (at constant P)}$

$\frac{V_f}{T_f}=\frac{V_i}{T_i}\text{ (at constant P)}$

The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)”

$\text{ V}\alpha \frac{\text{T}}{\text{P}}$

For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as

$\frac{P_f{V}_f}{T_f}=\frac{P_i{V}_i}{T_i}$

(b)

Interpretation Introduction

Interpretation:

The change of pressure by increasing the temperature by ${10}^{\circ }\text{C}$ through heating and then decreasing the volume in a 10.0 L flask containing ${\text{H}}_{\text{2}}$ gas at 20 atm has to be explained and compared with the starting pressure.

Concept Introduction:

Boyle’s law:

$\text{ V}\alpha \frac{1}{\text{P}}\text{ (at constant T)}$

$P_f{V}_f=P_i{\text{V}}_i\text{ (at constant T)}$

Charles’s law:

$\text{ V}\alpha \text{ T (at constant P)}$

$\frac{V_f}{T_f}=\frac{V_i}{T_i}\text{ (at constant P)}$

The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)”

$\text{ V}\alpha \frac{\text{T}}{\text{P}}$

For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as

$\frac{P_f{V}_f}{T_f}=\frac{P_i{V}_i}{T_i}$