Chapter 5, Problem 5.25QP

Interpretation Introduction

Interpretation:

The change in the volume of 22.4 L rigid box, when a sample of 1.00 mol of argon gas vented into the rigid box which already contains a 1.00 mol of nitrogen gas.

1. (a) Decrease the total gas pressure in the box by 50%.
2. (b) Occupy the entire 22.4 L volume of the box.
3. (c) Increase the total gas pressure in the box by less than 50%.
4. (d) Spread out into the box but the actual volume occupied by the gas cannot be known without pressure information.
5. (e)  Occupy only a volume of 11.2 L of the box, since there is already 1.0 mol of nitrogen present in the container.

Concept Introduction:

Effusion:

The diffusion of gas molecules through the small holes into an emptied space. So, the gas molecules diffuse through the holes rather than colliding with it. The molecules free enough to make a move from the positions, so the faster the movement of molecule the more possibly they encounter the hole. The rate of effusion depends on the average molecular speed

Graham law of effusion:

At constant pressure, constant temperature the rate of effusion of the gas is inversely proportional to square root of the molar mass of the gas.

$\frac{\text{Rate}{}_{\text{1}}}{\text{Rate}{}_{\text{2}}}\text{=}\sqrt{\frac{\text{Molar}{\text{mass}}_{\text{1}}}{\text{Molar}{\text{mass}}_{\text{2}}}}$