Chapter 5.3, Problem 5.3CC

(a)

Interpretation Introduction

Interpretation:

Among the given three 3.0 L flasks containing $\text{He}$, $\text{Ar}$ and $\text{Xe}$ each at a pressure of 878 mmHg, the flasks that contains the most atoms of gas has to be identified.

Concept Introduction:

Avogadro’s law: According to Avogadro’s law, equal volumes of gases contain same number of molecules at a given temperature and volume.

$\begin{array}{l}\text{Vα n (at}\text{a}\text{constant}\text{pressure)}\\ \text{or}\\ \frac{\text{V}}{\text{n}}\text{= k}\end{array}$

Where,

n = no. of molecules (in moles)

V = Volume

k = constant

(b)

Interpretation Introduction

Interpretation:

Among the given three 3.0 L flasks containing $\text{He}$, $\text{Ar}$ and $\text{Xe}$ each at a pressure of 878 mmHg, the flasks that has the greatest density of gas has to be identified.

Concept Introduction:

$\text{Density = }\frac{\text{mass}}{\text{volume}}$

(c)

Interpretation Introduction

Interpretation:

Among the given three 3.0 L flasks containing $\text{He}$, $\text{Ar}$ and $\text{Xe}$, if the $\text{He}$ flask were heated and the $\text{Ar}$ flask were cooled, the flask exerting highest pressure has to be identified

Concept Introduction:

Ideal Gas Law:

The ideal gas equation is:

$\text{PV = nRT}$

Where,

P is the pressure

V is the volume

T is the temperature

R is molar gas constant

n is the mole

(d)

Interpretation Introduction

Interpretation:

Among the given three 3.0 L flasks containing $\text{He}$, $\text{Ar}$ and $\text{Xe}$, if the temperature of $\text{He}$ was lowered while that of the $\text{Xe}$ was raised, the flasks having greatest number of moles of gas has to be identified

Concept Introduction:

Avogadro’s law: According to Avogadro’s law, equal volumes of gases contain same number of molecules at a given temperature and volume.

$\begin{array}{l}\text{Vα n (at}\text{a}\text{constant}\text{pressure)}\\ \text{or}\\ \frac{\text{V}}{\text{n}}\text{= k}\end{array}$

Where,

n = no. of molecules (in moles)

V = Volume

k = constant