The factor of volume of air got increased when it is taken from earth’s surface to the stratosphere has to be calculated Concept Introduction: Combined Gas Law : Boyle’s law: V α 1 P (at constant T) P f V f = P i V i (at constant T) Charles’s law: V α T (at constant P) V f T f = V i T i (at constant P) The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)” V α T P For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as P f V f T f = P i V i T i On rearranging, we get V f = V i × P i P f × T f T i Where, T i a n d T f are initial temperature and final temperature respectively V i a n d V f are initial volume and final volume respectively P i a n d P f are initial pressure and final pressure respectively
The factor of volume of air got increased when it is taken from earth’s surface to the stratosphere has to be calculated Concept Introduction: Combined Gas Law : Boyle’s law: V α 1 P (at constant T) P f V f = P i V i (at constant T) Charles’s law: V α T (at constant P) V f T f = V i T i (at constant P) The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)” V α T P For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as P f V f T f = P i V i T i On rearranging, we get V f = V i × P i P f × T f T i Where, T i a n d T f are initial temperature and final temperature respectively V i a n d V f are initial volume and final volume respectively P i a n d P f are initial pressure and final pressure respectively
Solution Summary: The author explains that the factor of volume of air got increased when it is taken from earth’s surface to the stratosphere has to be calculated.
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Study of body parts and their functions. In this combined field of study, anatomy refers to studying the body structure of organisms, whereas physiology refers to their function.
Chapter 5, Problem 5.110QP
Interpretation Introduction
Interpretation:
The factor of volume of air got increased when it is taken from earth’s surface to the stratosphere has to be calculated
Concept Introduction:
Combined Gas Law:
Boyle’s law:
Vα1P (at constant T)
PfVf=PiVi (at constant T)
Charles’s law:
Vα T (at constant P)
VfTf=ViTi (at constant P)
The boyle’s law and charles’s law is combined and stated as “the volume (V) of a given gas is directly proportional to temperature (T) and inversely proportional to pressure (P)”
VαTP
For a sample of gas supposing a change in temperature, volume and pressure, the combined gas law can be written as
PfVfTf=PiViTi
On rearranging, we get
Vf=Vi×PiPf×TfTi
Where,
Tiand Tf are initial temperature and final temperature respectively
Viand Vf are initial volume and final volume respectively
Piand Pf are initial pressure and final pressure respectively
Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
+ More...
Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
The following equations represent the formation of compound MX. What is the AH for the
electron affinity of X (g)?
X₂ (g) → 2X (g)
M (s) → M (g)
M (g)
M (g) + e-
AH = 60 kJ/mol
AH = 22 kJ/mol
X (g) + e-X (g)
M* (g) +X (g) → MX (s)
AH = 118 kJ/mol
AH = ?
AH = -190 kJ/mol
AH = -100 kJ/mol
a)
-80 kJ
b)
-30 kJ
c)
-20 kJ
d)
20 kJ
e)
156 kJ
Chapter 5 Solutions
General Chemistry - Standalone book (MindTap Course List)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell