Given that the sample of B 2 H 6 gas in a 35 mL container is at a pressure of 450. 0 mm Hg and a temperature of 62 5 o C . The new temperature in o C if the gas is allowed to cool at a constant volume until the pressure is 375 mm Hg should be calculated. Concept Introduction: The final volume of the gas at the varying pressure can be calculated using Gay-Lussac’s law, which states the relationship between pressure and temperature of the gas. According to Gay-Lussac’s Law, for the gas held at constant volume, the pressure of a given amount of gas is directly proportional to the temperature of the gas. Mathematically, it is given as. P ∝ T . P T = c o n s t a n t = k . We two different sets of temperature and pressure of the gas is considered, the above equation becomes as follows: P 1 T 1 = P 2 T 2 . where P 1 and T 1 are initial pressure and temperature of the gas, while P 2 and T 2 are final pressure and temperature of the gas.
Given that the sample of B 2 H 6 gas in a 35 mL container is at a pressure of 450. 0 mm Hg and a temperature of 62 5 o C . The new temperature in o C if the gas is allowed to cool at a constant volume until the pressure is 375 mm Hg should be calculated. Concept Introduction: The final volume of the gas at the varying pressure can be calculated using Gay-Lussac’s law, which states the relationship between pressure and temperature of the gas. According to Gay-Lussac’s Law, for the gas held at constant volume, the pressure of a given amount of gas is directly proportional to the temperature of the gas. Mathematically, it is given as. P ∝ T . P T = c o n s t a n t = k . We two different sets of temperature and pressure of the gas is considered, the above equation becomes as follows: P 1 T 1 = P 2 T 2 . where P 1 and T 1 are initial pressure and temperature of the gas, while P 2 and T 2 are final pressure and temperature of the gas.
Solution Summary: The author explains that the final volume of the gas at the varying pressure can be calculated using Gay-Lussac’s law.
Given that the sample of B2H6 gas in a 35 mL container is at a pressure of 450.0 mm Hg and a temperature of 625 oC. The new temperature in oC if the gas is allowed to cool at a constant volume until the pressure is 375 mm Hg should be calculated.
Concept Introduction:
The final volume of the gas at the varying pressure can be calculated using Gay-Lussac’s law, which states the relationship between pressure and temperature of the gas.
According to Gay-Lussac’s Law, for the gas held at constant volume, the pressure of a given amount of gas is directly proportional to the temperature of the gas. Mathematically, it is given as.
P∝T.
PT=constant=k.
We two different sets of temperature and pressure of the gas is considered, the above equation becomes as follows:
P1T1=P2T2.
where P1 and T1 are initial pressure and temperature of the gas, while P2 and T2 are final pressure and temperature of the gas.
Draw the structure of the product of the reaction given the IR and MS data.
Spectral analysis of the product reveals:
MS: M 150, M-15, M-43
CH.COCI
AICI,
IR: 3150-3000 cm, 2950-2850 cm
and 1700 cm
Part II. Identify whether the two protons in blue are homotopic, enantiopic, diasteriotopic, or heterotopic.
a)
HO
b)
Bri
H
HH
c)
d)
H
H H Br
0
None
Chapter 5 Solutions
Bundle: Introduction to General, Organic and Biochemistry, 11th + OWLv2, 4 terms (24 months) Printed Access Card
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell