
(a)
Interpretation:
Find if the given statement is true or false.
“
Concept Introduction:
According to Avogadro’s law states that equal volume of gas at the same temperature and pressure contain equal number of molecules.

Answer to Problem 5.36P
Explanation of Solution
Given information:
According to the Avogadro’s law, equal volume of gas at the same temperature and pressure contain equal number of molecules.
(b)
Interpretation:
Find if the given statement is true or false.
“At STP, one mole of uranium hexafluoride occupies a volume of
Concept Introduction:
Mathematically,
Where,

Answer to Problem 5.36P
At STP, one mole of uranium hexafluoride occupies a volume of
Explanation of Solution
At STP,
We know that, as per ideal
Now, we need to calculate volume.
Substituting the values, we get.
Hence, at STP, one mole of uranium hexafluoride occupies a volume of
(c)
Interpretation:
Find if the given statement is true or false.
“If two gas samples have the same temperature, volume and pressure, the both contain same number of molecules.”
Concept Introduction:

Answer to Problem 5.36P
If two gas samples have the same temperature, volume and pressure, the both contain same number of molecules. Thus, the given statement is true.
Explanation of Solution
According to
(d)
Interpretation:
Find if the given statement is true or false.
“The value of
Concept Introduction:
Avogadro’s law states that equal volume of gas at the same temperature and pressure contain equal number of molecules.

Answer to Problem 5.36P
The value of Avogadro’s number is
Explanation of Solution
Avogadro’s number is defined as number of units in 1 mole of a substance. According to Avogadro’s law, there are
Thus, Avogadro’s number is equal to
(e)
Interpretation:
Find if the given statement is true or false.
“Avogadro’s number is valid only for gases at STP.”
Concept Introduction:
Avogadro’s number is a total number of units in one mole of any substance.
Avogadro’s number is equal to

Answer to Problem 5.36P
Avogadro’s number is valid for gases at any temperature or pressure value. Thus, the given statement is false.
Explanation of Solution
Avogadro’s law states that equal volume of gas at the same temperature and pressure contain equal number of molecules.
At any temperature or pressure value, the number of atoms or molecules in one mol of a substance is equal to Avogadro’s number that is
(f)
Interpretation:
Find if the given statement is true or false.
“The ideal gas law is
Concept Introduction:
Mathematically, Ideal gas law states that:
Where,

Answer to Problem 5.36P
The ideal gas law is
Explanation of Solution
Given information:
The ideal gas law is
Mathematically, Ideal gas law states that:
(g)
Interpretation:
Find if the given statement is true or false.
“When using the ideal gas law for calculations, temperature must be in degrees Celsius.”
Concept Introduction:
Mathematically, Ideal gas law states that:
Where,

Answer to Problem 5.36P
When using the ideal gas law for calculations, temperature must be in Kelvin. Thus, the given statement is False.
Explanation of Solution
When we are using ideal gas law for calculations, temperature must be in Kelvin. The temperature can never be in Celsius. This is because
(h)
Interpretation:
Find if the given statement is true or false.
“If one mole of ethane gas occupies
Concept Introduction:
Mathematically, Ideal gas law states that:
Where,

Answer to Problem 5.36P
If one mole of ethane gas occupies
Explanation of Solution
We have
We know that, as per ideal gas law,
Now, we need to calculate volume.
Substituting the values, we get.
Hence, if one mole of ethane gas occupies
(i)
Interpretation:
Find if the given statement is true or false.
“One mole of helium gas at STP occupies twice the volume of one mole of hydrogen”.
Concept Introduction:
According to Avogadro’s law states that equal volume of gas at the same temperature and pressure contain equal number of molecules.

Answer to Problem 5.36P
One mole of helium gas at STP occupies same the volume of one mole of hydrogen. Thus, the given statement is false.
Explanation of Solution
Given information:
One mole of helium gas at STP occupies twice the volume of one mole of hydrogen
According to Avogadro’s law, equal volume of gas at the same temperature and pressure contain equal number of molecules We have one mole of helium gas at STP and one mole of hydrogen gas at STP.
One mole of any substance will occupy
Want to see more full solutions like this?
Chapter 5 Solutions
Bundle: Introduction to General, Organic and Biochemistry, 11th + OWLv2, 4 terms (24 months) Printed Access Card
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Priva ×arrow_forwardPredict the products of this organic reaction: Explanation Check IN NaBH3CN H+ ? Click and drag to start drawing a structure. D 5 C +arrow_forwardPredict the products of this organic reaction: H3O+ + ? • Draw all the reasonable products in the drawing area below. If there are no products, because no reaction will occur, check the box under the drawing area. • Include both major and minor products, if some of the products will be more common than others. • Be sure to use wedge and dash bonds if you need to distinguish between enantiomers. No reaction. Click and drag to start drawing a structure. dmarrow_forward
- Iarrow_forwardDraw the anti-Markovnikov product of the hydration of this alkene. this problem. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for esc esc ☐ Explanation Check F1 1 2 F2 # 3 F3 + $ 14 × 1. BH THE BH3 2. H O NaOH '2 2' Click and drag to start drawing a structure. F4 Q W E R A S D % 905 LL F5 F6 F7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility < & 6 7 27 8 T Y U G H I F8 F9 F10 F11 F12 9 0 J K L P + // command option Z X C V B N M H H rol option commandarrow_forwardAG/F-2° V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: -0.93 +0.38 -0.50 -0.51 -0.06 H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3 Acidic solution Basic solution -0.28 -0.50 3--1.12 -1.57 -2.05 -0.89 PO HPO H₂PO₂ →P → PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH P 0.0 -0.5 -1.0- -1.5- -2.0 H.PO, -2.3+ -3 -2 -1 1 2 3 2 H,PO, b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) H,PO 4 S Oxidation stale, Narrow_forward
- 4. For the following complexes, draw the structures and give a d-electron count of the metal: a) Tris(acetylacetonato)iron(III) b) Hexabromoplatinate(2-) c) Potassium diamminetetrabromocobaltate(III) (6 points)arrow_forward2. Calculate the overall formation constant for [Fe(CN)6]³, given that the overall formation constant for [Fe(CN)6] 4 is ~1032, and that: Fe3+ (aq) + e = Fe²+ (aq) E° = +0.77 V [Fe(CN)6]³ (aq) + e¯ = [Fe(CN)6] (aq) E° = +0.36 V (4 points)arrow_forward5. Consider the compounds shown below as ligands in coordination chemistry and identify their denticity; comment on their ability to form chelate complexes. (6 points) N N A B N N N IN N Carrow_forward
- 1. Use standard reduction potentials to rationalize quantitatively why: (6 points) (a) Al liberates H2 from dilute HCl, but Ag does not; (b) Cl2 liberates Br2 from aqueous KBr solution, but does not liberate C12 from aqueous KCl solution; c) a method of growing Ag crystals is to immerse a zinc foil in an aqueous solution of AgNO3.arrow_forwardWhat would be the best choices for the missing reagents 1 and 3 in this synthesis? 1 1. PPh3 2. n-BuLi 3 2 • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure. Xarrow_forwardWhat is the missing reactant R in this organic reaction? N N H3O+ +R + • Draw the structure of R in the drawing area below. • Be sure to use wedge and dash bonds if it's necessary to draw one particular enantiomer. Click and drag to start drawing a structure. fmarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





