Chapter 5, Problem 5.103P

Interpretation Introduction

(a)

Interpretation:

To interpret the fact that when the propane is put under pressure it can be liquefied.

Concept Introduction:

When a gas is pressurized, the molecules of gas come closer. The intermolecular forces pull molecules together, forming a liquid. This results in a change of phase from gas to liquid.

Interpretation Introduction

(b)

Interpretation:

The kilogram of propane in full tank should be determined.

Concept Introduction:

A conversion factor is a numerical ratio which is used to show a measurement in one unit as another unit. It is always equal to 1.

To solve this problem, the following conversion factor is used:

$\text{1 lb = 0}\text{.455 kg}$.

Interpretation Introduction

(c)

Interpretation:

The number of moles of propane of full tank should be determined.

Concept Introduction:

The number of moles of any substance is related to mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass and m is molar mass.

Interpretation Introduction

(d)

Interpretation:

The volume of flexible container containing propane should be determined.

Concept Introduction:

The ideal gas equation is as follows:

$PV=nRT$

Here, p is pressure of the gas, v is volume of the gas, n is number of moles, r is gas constant and t is temperature.