
Interpretation:
Compound that contains one carbon atom and two oxygen atom is named as carbon dioxide rather than dioxygen monocarbide and the reason for this has to be given.
Concept Introduction:
Molecular compound that contains only two nonmetallic elements in it is known as Binary molecular compound. Naming a binary molecular compound is similar to that of a binary ionic compound. A major difference is that the binary molecular compound contain numerical prefixes which gives the information about the number of atoms of same kind are present in it.
For naming a binary molecular compound, the element that has lower electronegativity is given first and that is followed by a stem of the name of the nonmetal that is more electronegative and the suffix “-ide”. Numerical prefixes are added to both nonmetals to indicate the number of atoms present in it.
Some binary molecular compounds have names that are no way related to the naming rules. They are common names that are given for the compounds before the systematic rule development.
Chemical formula is a representation of the total number of same type of atoms that is present in the molecule. The chemical formula for binary compounds can be identified from the prefix that is present in the two words of the name of binary compounds. The prefix is put as number in subscript after the atomic symbol.

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Chapter 5 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- Please label this COZY spectraarrow_forwardPlease label this HNMRarrow_forwardConsider the following gas chromatographs of Compound A, Compound B, and a mixture of Compounds A and B. Inject A B mixture Area= 9 Area = 5 Area = 3 Area Inject . མི། Inject J2 What is the percentage of Compound B in the the mixture?arrow_forward
- Rank these according to stability. CH3 H3C CH3 1 CH3 H3C 1 most stable, 3 least stable O 1 most stable, 2 least stable 2 most stable, 1 least stable O2 most stable, 3 least stable O3 most stable, 2 least stable O3 most stable, 1 least stable CH3 2 CH3 CH3 H₂C CH3 3 CH3 CHarrow_forwardConsider this IR and NMR: INFRARED SPECTRUM TRANSMITTANCE 0.8- 0.6 0.4 0.2 3000 10 9 8 00 HSP-00-541 7 CO 6 2000 Wavenumber (cm-1) сл 5 ppm 4 M Which compound gave rise to these spectra? N 1000 1 0arrow_forwardConsider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> C2H4Cl 2 MW = 26 36.5 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?arrow_forward
- What is the name of the major product of this reaction? OH CH3 H₂SO4, heat 1-methylcyclohexene O2-methyl-1-cyclohexene O 3-mthylcyclohexene 1-methyl-2-cyclohexenearrow_forwardWe added a brown solution of Br2 to one of our products, and the brown color disappeared. This indicated that our product wasarrow_forwardRank the following according to reactivity toward nitration: a) benzene b) bromobenzene c) nitrobenzene d) phenol Od) greatest, c) least Od) greatest, b) least Od) greatest, a) least a) greatest, b) least a) greatest, c) least Oa) greatest, d) least Ob) greatest, a) least O b) greatest, c) least Ob) greatest, d) least O c) greatest, a) least O c) greatest, b) least O c) greatest, d) leastarrow_forward
- O-Nitrophenol was distilled over with the steam in our experiment while the other isomer did not. This is due to: O intramolecular hydrogen bonding in the ortho isomer O intermolecular hydrogen bonding in the the ortho isomer O the ortho isomer has a lower density O the ortho isomer has a lower molecular weightarrow_forwardK 44% Problem 68 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :6: :: :CI: CI CI: :0:0 Select to Add Arrows Select to Add Arrows H H Cl CI: CI CI: Select to Add Arrows Select to Add Arrows H :CI: Alarrow_forwardI I H :0: Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. 0:0 :0: CI ΑΙ :CI: :CI: :0: CI Select to Add Arrows Select to Add Arrows cl. :0: Cl © ハ CI:: CI H CO Select to Add Arrows Select to Add Arrows 10: AI ::arrow_forward
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