Consider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> C2H4Cl 2 MW = 26 36.5 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?
Consider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> C2H4Cl 2 MW = 26 36.5 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?
Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter7: Chemical Energy
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Transcribed Image Text:Consider this reaction (molecular weights are under each compound):
HC=CH
+
2 HCI -->
C2H4Cl 2
MW = 26
36.5
99
If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are
actually produced, what is the percent yield?
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