Assign this H NMR Normalized Intensity0.400.350.300.250.205$ 0.150.100.051.001.02 0.9882311OH100.971.003.106.29

Multiplicity of proton NMR is given by the formula n+1 where 'n' is the number of hydrogens on the…

Answered: Normalized Intensity 0.40 0.35 0.30…

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter3: Measurement And Chemical Calculations

Section: Chapter Questions

Problem 5E

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How do I include units into my slope intercept Units - g mL 1. Y=1.2534x+0.0250 Answer- Y=1.2534x ( mL ) + 0.0250 (g) 2. Y = 0.997x + 0.0585 Answers y=0.997x(mL) + 0.0585 (g)
Suppose some measurements are made on two different homogeneous stones to find out if they are made of the same kind of rock. The mass and volume measurements are listed below. Are the two stones the same type of rock? Why or why not? Show all calculations. Mass Volume Calculations Stone 1 58.0 g 20.0 cm Stone 2 50.1 g 15.0 cm3 21/common/assets/pdfjs/1.0.0.30/web/viewer.ht...ndered-pdf&fullscreen=Dd21-fileviewer-rendered-pdf-dialog&height=746#0
100- 8 8 Relative Intensity $ 20- 0- Relative Intensity 10 200- 80- 40- 20- 0- 10 20 30 m/z 20 20 100 $10 Chlorine OR Bromine OR Neither Chlorine OR Bromine OR Neither 90 100 100- Relative Intensity DO- ģ 20- 0 100 80 10 8 Relative Intensity 3 0- 10 40 30 60 15 m/z Chlorine OR Bromine OR Neither 35 40 45 m/z weytekakumpumakija 30 100 110 55 Chlorine OR Bromine OR Neither
For each problem, you must: 1) Calculate the degree of unsaturation. -1 2) Assign the principal IR absorption bands above 1500 cm 3) Draw the structure of the compound 4) Label the protons on your structure with letters and assign them to peaks on the NMR spectrum (see the example below). 4.0 C 2H 3.5 3.0 2.5 D 1H 3.0 This peak is a magnified version of this peak A 2.8 2.0 1H B zum 2.6 B 2H Each problem contains the formula of the compound, the IR spectrum (with axes in cm³¹ vs. % transmission), and the ¹H NMR spectrum (with axis in PPM shift). Some NMR spectra show a peak hovering above the baseline. This is a magnified view of one of the actual peaks, to allow you to see splitting more clearly. 1.5 2.4 OHD A 3H 1.0 PPM 0.5
What can be concluded from this table?
Fill in all empty spaces. (Round the answers to one decimal place)
7.The word pour is commonly used in reference to liquids but not to solids or gases. Can you pour a solid or a gas? Why or why not? If either answer is yes, can you give an example?
Hexane (C6H14, density = 0.766 g/cm3), perfluoro-hexane (C6F14, density = 1.669 g/cm3), and water are immiscible liquids; that is, they do not dissolve in one another. You place 10 mL of each in a graduated cylinder, along with pieces of high-density polyethylene (HDPE, density = 0.97 g/cm3), polyvinyl chloride(PVC, density = 1.36 g/cm3), and Teflon (density = 2.3 g/cm3). None of these common plastics dissolves in these liquids. Describe what you expect to see.
P₁-1. 8568 = P₂= 1.3513 P₁= 1.0282 0.8197 06975 Po= 10 603 3 P₁= 0 5349 P4= Pressure (atm) Ps= V₁-5.0 V₂ = 7.5 V₁ - 10.0 V₁= 12.5 Vs = 15.0 V₁= 17.5 V₁=20.0 Volume (mL) Constant, k Kavg= 1. Is the relationship between the pressure and volume of a confined gas direct or inverse? 2. Calculate k (to 2 decimal places) for the seven data pairs in your data table. Calculate an average. Show your calculations in your lab notebook. Record the answers in the third column of the Summary Data Table. 3. Using P, V, and k, write an equation representing Boyle's law. 4. What would the pressure be if the volume of the syringe was increased to 40.0 mL? Include a calculation in your lab notebook to support your answer. atm 5. What would the pressure be if the volume of the syringe was decreased to 2.5 mL? Include a calculation in your lab notebook to support your answer. atm
IA VIIIA 4.003 1.008 VIA VILA He 10.81 12011 14.007 15999 18.998 20.179 MA IVA VA 6.941 9.012 u „Be „B .C N ,0 F Ne 22.990 24 305 „Na „Mg ma VB 26.98 28.09 30.974 32.06 35 453 39948 m Al „Si 1sP S „CI „Ar 39 098 40.08 4496 47 88 50.94 52.00 54.94 5.85 58.93 58 89 63.546 65. 38 69.72 7259 7492 78.96 79.904 8380 „KCaSc zTI V „CrMnFe „Co Ni „CuZn „Ga„Ge As Se „Br Kr 101.1 102 91 106.4 107 87 112 41 114.82 118.69 121.75 127 60 126 90 13129 „Rb „Sr „Y Zr „Nb MoTc„RuRh Pd Ag.cd In „Sn Sb Te l Xe VIIIB VB VIB VIB 21 85.47 87.62 88.91 9122 291 9594 50° 52 132 91 137 33 138.91 178.49 18095 183.85 186 2 190 2 1922 195.08 196.97 200 59 204 38 2072 208 98 44) 210) e22) „CsBa „La zHf „Ta „W „Re„Os ir „Pt Au Hg I Pb Bi „PoAtRn 023) 226 03 227.03 „Fr Ra „Ac 72 73 140. 12 140.908 144 24 (145) 150 36 15196 157 25 158.93 162 50 164.93 167 26 168 93 173 04 17497 „Ce „Pr NdPm SmEu „Gd Tb „Dy „Ho Er „Tm„Yb „Lu G51) 232 04 231036238 03 237 05 Q4) 43) 247) 47) „Th „Pa U Np „PuAm.Cm „Bk Cf „EsFmMdNo Lr 054)…
14.98+27,340+87.7593
1/T(K) ln(p) 0.00341 -4.33 0.00295 -1.335 0.00267 0 Graph the following using excel

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Normalized Intensity 0.40 0.35 0.30 0.25 0.20 5 $ 0.15 0.10 0.05 1.00 1.02 0.98 8 2 3 11 OH 10 0.97 1.00 3.10 6.29