Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 5, Problem 29CQ
To determine
The microstructure of iron
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Chapter 5 Solutions
Materials Science And Engineering Properties
Ch. 5 - Prob. 1CQCh. 5 - Prob. 2CQCh. 5 - Prob. 3CQCh. 5 - Prob. 4CQCh. 5 - Prob. 5CQCh. 5 - Prob. 6CQCh. 5 - Prob. 7CQCh. 5 - Prob. 8CQCh. 5 - Prob. 9CQCh. 5 - Prob. 10CQ
Ch. 5 - Prob. 11CQCh. 5 - Prob. 12CQCh. 5 - Prob. 13CQCh. 5 - Prob. 14CQCh. 5 - Prob. 15CQCh. 5 - Prob. 16CQCh. 5 - Prob. 17CQCh. 5 - Prob. 18CQCh. 5 - Prob. 19CQCh. 5 - Prob. 20CQCh. 5 - Prob. 21CQCh. 5 - Prob. 22CQCh. 5 - Prob. 23CQCh. 5 - Prob. 24CQCh. 5 - Prob. 25CQCh. 5 - Prob. 26CQCh. 5 - Prob. 27CQCh. 5 - Prob. 28CQCh. 5 - Prob. 29CQCh. 5 - Prob. 30CQCh. 5 - Prob. 31CQCh. 5 - Prob. 32CQCh. 5 - Prob. 33CQCh. 5 - Prob. 34CQCh. 5 - Prob. 35CQCh. 5 - Prob. 36CQCh. 5 - Prob. 1ETSQCh. 5 - Prob. 2ETSQCh. 5 - Prob. 3ETSQCh. 5 - Prob. 4ETSQCh. 5 - Prob. 5ETSQCh. 5 - Prob. 6ETSQCh. 5 - Prob. 7ETSQCh. 5 - Prob. 8ETSQCh. 5 - Prob. 9ETSQCh. 5 - Prob. 10ETSQCh. 5 - Prob. 11ETSQCh. 5 - Prob. 12ETSQCh. 5 - Prob. 1DRQCh. 5 - Prob. 2DRQCh. 5 - Prob. 3DRQCh. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. 5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. 5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10PCh. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19P
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- In an engineering application, the material is a strip of iron with a fixed crystallographic structure subject to a tensile load during operation. The part failed (yielded) during operation and needs to be replaced with a component with better properties. You are told that two other iron strips had failed at yield stresses of 110 and 120 MPa, with grain sizes of 30 microns and 25 microns respectively. The current strip has a grain size of 20 microns. The diameter of the rod is 1 mm and the load applied is 100 N. What is the yield stress of the new part C and would you recommend it for operation? Select one: Oa. 133.5 MPa, yes O b. OC. Od Oe. 120.5 MPa, no 129.5, yes 140.5, no 123.5 MPa, yesarrow_forwardMaterials, properties and testing Describe the effect bend testing have on the thermal properties of steel.arrow_forward16) Which of the following mechanical properties can be measured / calculated from this tensile stress-strain graph of a generic metal alloy? (pick all that apply) a. Poisson's ratio b. Elastic modulus C. Shear modulus d. Flexural modulus e. Fracture toughness 17) Interstitial sites in a FCC lattice are called a. Rhombohedral and cubic b. Cubic and hexagonal C. Monoclinic and triclinic Stress (MPa) 2000 MPa 2000 1000 1000 0.000 0.005 0.010 0.015 Strain 0.000 0.020 0.040 Strain 0.060 0.080 d. Tetrahedral and octahedral e. Heterogeneous and homogeneous 18) Traditional photovoltaics rely on which structural feature to separate charge carriers? a. The p-n junction b. The grain boundaries C. The twin boundaries d. The electron-hole pair e. The band gap 19) The process by which lithium ions move in to and out of graphite in a lithium-ion battery is called a. Intercalation b. Stacking C. Precipitation d. Phase combination e. lonization 20) A polymer obtained by the polymerization of two types…arrow_forward
- Which of the following statements is incorrect about ceramics? A Ceramics have very weak interatomic bonding. (B) Ceramics have a low coefficient of thermal expansion © Ceramics can be crystalline or nanocrystalline (amorphous). (D Ceramics can be used as a matrix material in composites.arrow_forwardAt a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; α=α=12.5 x 10-6/°F] bar with a width of 2.5 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; α=α=9.6 x 10-6/°F] bar with a width of 1.7 in. and a thickness of 0.75 in. The supports at A and C are rigid. Assume h1=2.5 in., h2=1.7 in., L1=31 in., L2=46 in., and Δ=Δ= 0.04 in. (A) Determine the lowest temperature, Tcontact, at which the two bars contact each other. (B) Find a geometry-of-deformation relationship for the case in which the gap is closed. Express this relationship by entering the sum δ1+δ2, where δ1 is the axial deflection of Bar (1), and δ2 is the axial deflection of Bar (2). δ1+δ2= _____in. (C) Find the force in the Bar (1), F1, and the force in Bar (2), F2, at a temperature of 225oF. By convention, a tension force is positive and a compression force is negative. IN KIPS (D) Find σ1 and σ2,…arrow_forwardAt a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 12.5 x 10-6/°F] bar with a width of 3.0 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 9.6 x 10-6/°F] bar with a width of 2.0 in. and a thickness of 0.75 in. The supports at A and C are rigid. Determine (a) the lowest temperature at which the two bars contact each other. (b) the normal stress in the two bars at a temperature of 250°F. (c) the normal strain in the two bars at 250°F. (d) the change in width of the aluminum bar at a temperature of 250°F. (1) 3.0 in. 32 in. 2.0 in. B ↓ (2) 44 in. 0.04-in. gap Determine the lowest temperature, Tcontact, at which the two bars contact each other.arrow_forward
- At a temperature of 60°F, a 0.02-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; α=α=12.5 x 10-6/°F] bar with a width of 2.8 in. and a thickness of 0.85 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; α=α=9.6 x 10-6/°F] bar with a width of 1.6 in. and a thickness of 0.85 in. The supports at A and C are rigid. Assume h1=2.8 in., h2=1.6 in., L1=26 in., L2=40 in., and Δ=Δ= 0.02 in. Determine(a) the lowest temperature at which the two bars contact each other.(b) the normal stress in the two bars at a temperature of 225°F.(c) the normal strain in the two bars at 225°F.(d) the change in width of the aluminum bar at a temperature of 225°F.arrow_forwardWhich one of the following processes causes a dramatic increase in the hardness of a steel part? A) quenching B) tempering (c) normalizing D full annealingarrow_forward2arrow_forward
- 29) Copper and nickel have an isomorphous phase diagram. Label which curve best matches the GENERAL TREND expected for the following properties (fill in the blank): Ductility (elongation): Yield Strength: Electrical resistivity: Note: you can use the same line for multiple properties if you choose. Modulus, Strength, Resistivity 3 A B C wt% Ni Niarrow_forwardAt a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 13.4 x 10-6/°F] bar with a width of 3 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 10.1 x 10-6/°F] bar with a width of 2 in. and a thickness of 0.75 in. The supports at A and Care rigid. Determine the lowest temperature at which the two bars contact each other. (1) ↑ 3 in. 32 in. O 75.9°F O 146.5°F O 105.8°F O 122.3°F O 111.3°F 2 in. (2) 44 in. -0.04-in. gaparrow_forwardAt a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 14.4 x 10-6/°F] bar with a width of 3 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 9.6 × 10-6/°F] bar with a width of 2 in. and a thickness of 0.75 in. The supports at A and Care rigid. Determine the lowest temperature at which the two bars contact each other. (1) 3 in. 32 in. 105.3°F 75.3°F O 147.3°F 86.6°F 113.4°F B ↑ 2 in. ↓ (2) 44 in. 0.04-in. gaparrow_forward
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