a. //Initialize the variables int n=1; int k=2; int r=n; //Check the condition if (k<n) { //Assign k to r r=k } Value of each variable after “ if ” statement: n=1, k=2, r=1 Explanation: The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

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Answer 1

Expert Solution & Answer

Chapter 5, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

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reminder it an exercice not a grading work GETTING STARTED Open the file SC_EX19_EOM2-1_FirstLastNamexlsx, available for download from the SAM website. Save the file as SC_EX19_EOM2-1_FirstLastNamexlsx by changing the “1” to a “2”. If you do not see the .xlsx file extension in the Save As dialog box, do not type it. The program will add the file extension for you automatically. With the file SC_EX19_EOM2-1_FirstLastNamexlsx still open, ensure that your first and last name is displayed in cell B6 of the Documentation sheet. If cell B6 does not display your name, delete the file and download a new copy from the SAM website. Brad Kauffman is the senior director of projects for Rivera Engineering in Miami, Florida. The company performs engineering projects for public utilities and energy companies. Brad has started to create an Excel workbook to track estimated and actual hours and billing amounts for each project. He asks you to format the workbook to make the…

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Answer 2

Expert Solution & Answer

Chapter 5, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

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Answer 3

Expert Solution & Answer

Chapter 5, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

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Answer 4

Expert Solution & Answer

Chapter 5, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

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Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 5, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 8

Chapter 5, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Answer 9

Chapter 5, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Answer 10

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Answer 11

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Answer 12

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Answer 13

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Answer 14

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 15

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 16

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