Tracing the given pseudocode with the below values: “start1” = 10 “end1” = 12 “start2” = 11 “end2” = 13 Tracing: The first “if” condition fails because, “start1” is not greater than “start2” (10 is not greater than 11) and therefore, it goes to the “else” part and assigns the value “start2” to “s”. Now “s” = 11. The second “if” condition becomes true because, “end1” is less than “end2” (12 is less than 13). The value of “end1” will be assigned to “e”. Now “e” = 12. The third “if” condition becomes true because, “s” is less than “e” (11 is less than 12). The string “The appointments overlap” will be printed...

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Chapter 5, Problem 12RE

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Tracing the given pseudocode with the below values:

“start1” = 10

“end1” = 12

“start2” = 11

“end2” = 13

Tracing:

The first “if” condition fails because, “start1” is not greater than “start2” (10 is not greater than 11) and therefore, it goes to the “else” part and assigns the value “start2” to “s”.

Now “s” = 11.

The second “if” condition becomes true because, “end1” is less than “end2” (12 is less than 13). The value of “end1” will be assigned to “e”.

Now “e” = 12.

The third “if” condition becomes true because, “s” is less than “e” (11 is less than 12). The string “The appointments overlap” will be printed...

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