Chapter 5, Problem 3RE

Explanation of Solution

a.

Given:

if x>0 then System.out.print(x)

Error #1:

There is no parenthesis around “x>0”. The “if” statement should be enclosed with “( )” around the condition...

Explanation of Solution

b.

Given:

if (1+x> Math.pow(x,Math.sqrt(2)){ y=y+x;}

Error #1:

In the given statem...

Explanation of Solution

c.

Given:

if (x=1){y++;}

Error #1:

In the given statement, there is only ...

Explanation of Solution

d.

Given:

//Get the integer value

x = in.nextInt();

//Check whether the value is integer

if (in.hasNextInt())

{

    //Add the sum with x

    sum = sum + x;

}

//Otherwise

else

{

    //Print the output

    System.out.println("Bad input for x");

}

Error #1:

In the code snipped statement, the programmer tries to validate the input. The “x=in.nextInt()” should be placed inside the “if” statement rather than placing it outside the “if” statement...

Explanation of Solution

e.

Given:

//Get the string value

String letterGrade = "F";

//Check the grade value is greater than or equal to 90 and assign "A"

if (grade >= 90) { letterGrade = "A"; }

//Check the grade value is greater than or equal to 80 and assign "B"

if (grade >= 80) { letterGrade = "B"; }

//Check the grade value is greater than or equal to 70 and assign "C"

if (grade >= 70) { letterGrade = "C"; }

//Check the grade value is greater than or equal to 60 and assign "D"

if (grade >= 60) { letterGrade = "D"; }

Error #1:

The given code snippet should be enclosed with “if else” statement rather than single “if” statement...