Chapter 4.8, Problem 30E

Solution

To find: The $\omega$ for the tuning fork.

  $\omega =1056\pi \text{ radians/sec}$

Given information:

Given, a point on the tip of a tuning fork vibrates in harmonic motion described by the equation $d=14\sin \omega t$ . The frequency is 528 vibrations per second.

Calculation:

Given frequency is 528 vibrations per second.

But the frequency is given by:

  $\begin{array}{l}f=528\\ \frac{\omega }{2\pi }=528\\ \omega =528\left(2\pi \right)\\ \omega =1056\pi \end{array}$

Hence,

  $\omega =1056\pi \text{ radians/sec}$ .

Conclusion:

  $\omega =1056\pi \text{ radians/sec}$