
Mechanics of Materials (10th Edition)
10th Edition
ISBN: 9780134319650
Author: Russell C. Hibbeler
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 4.2, Problem 4.27P
Solve Prob. 4–26 when the load P acts vertically downward at C.
Probs. 4–26/27
Expert Solution & Answer

Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
!
Required information
Air at 25°C (cp=1006 J/kg.K) is to be heated to 58°C by hot oil at 80°C (cp = 2150 J/kg.K) in a cross-flow heat exchanger
with air mixed and oil unmixed. The product of heat transfer surface area and the overall heat transfer coefficient is 750
W/K and the mass flow rate of air is twice that of oil.
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Air
Oil
80°C
Determine the effectiveness of the heat exchanger.
In an industrial facility, a counter-flow double-pipe heat exchanger uses superheated steam at a temperature of 155°C to
heat feed water at 30°C. The superheated steam experiences a temperature drop of 70°C as it exits the heat exchanger.
The water to be heated flows through the heat exchanger tube of negligible thickness at a constant rate of 3.47 kg/s. The
convective heat transfer coefficient on the superheated steam and water side is 850 W/m²K and 1250 W/m²K,
respectively. To account for the fouling due to chemical impurities that might be present in the feed water, assume
a fouling factor of 0.00015 m²-K/W for the water side.
The specific heat of water is determined at an average temperature of (30 +70)°C/2 = 50°C and is taken to be
J/kg.K.
Cp=
4181
Water
Steam
What would be the required heat exchanger area in case of parallel-flow arrangement?
The required heat exchanger area in case of parallel-flow arrangement is
1m².
A single-pass crossflow heat exchanger is used to cool jacket water (cp = 1.0 Btu/lbm.°F) of a diesel engine from 190°F to 140°F, using
air (Cp = 0.245 Btu/lbm.°F) at inlet temperature of 90°F. Both air flow and water flow are unmixed. If the water and air mass flow rates
are 85500 lbm/h and 400,000 lbm/h, respectively, determine the log mean temperature difference for this heat exchanger. Assume
the correction factor F to be 0.92.
Air flow
(unmixed)
Water flow
(unmixed)
The log mean temperature difference of the heat exchanger is
°F.
Chapter 4 Solutions
Mechanics of Materials (10th Edition)
Ch. 4.2 - In each case, determine the internal normal force...Ch. 4.2 - Determine the internal normal force between...Ch. 4.2 - The post weighs 8kN/m. Determine the internal...Ch. 4.2 - The rod is subjected to an external axial force of...Ch. 4.2 - The rigid beam supports the load of 60 kN....Ch. 4.2 - The 20-mm-diameter A-36 steel rod is subjected to...Ch. 4.2 - Segments AB and CD of the assembly are solid...Ch. 4.2 - The 30-mm-diameter A992 steel rod is subjected to...Ch. 4.2 - If the 20-mm-diameter rod is made of A-36 steel...Ch. 4.2 - The 20-mm-diameter 2014-T6 aluminum rod is...
Ch. 4.2 - The 20-mm-diameter 2014-T6 aluminum rod is...Ch. 4.2 - The A992 steel rod is subjected to the loading...Ch. 4.2 - The copper shaft is subjected to the axial loads...Ch. 4.2 - The composite shaft, consisting of aluminum,...Ch. 4.2 - The composite shaft, consisting of aluminum,...Ch. 4.2 - The 2014-T6 aluminium rod has a diameter of 30 mm...Ch. 4.2 - The A-36 steel drill shaft of an oil well extends...Ch. 4.2 - The truss is made of three A-36 steel members,...Ch. 4.2 - The truss is made of three A-36 steel members,...Ch. 4.2 - The assembly consists of two 10-mm diameter red...Ch. 4.2 - The assembly consists of two 10-mm diameter red...Ch. 4.2 - The load is supported by the four 304 stainless...Ch. 4.2 - The load is supported by the four 304 stainless...Ch. 4.2 - The rigid bar is supported by the pin-connected...Ch. 4.2 - The post is made of Douglas fir and has a diameter...Ch. 4.2 - The post is made of Douglas fir and has a diameter...Ch. 4.2 - The coupling rod is subjected to a force of 5 kip....Ch. 4.2 - The pipe is stuck in the ground so that when it is...Ch. 4.2 - The is made of three pin-connected A992 steel...Ch. 4.2 - The linkage is made of three pin connected A992...Ch. 4.2 - The assembly consists of three titanium...Ch. 4.2 - The rigid beam is supported at its ends by two...Ch. 4.2 - The rigid beam is supported at its ends by two...Ch. 4.2 - The steel bar has the original dimensions shown in...Ch. 4.2 - Determine the relative displacement of one end of...Ch. 4.2 - The assembly consists of two rigid bars that are...Ch. 4.2 - The truss consists of three members, each made...Ch. 4.2 - Solve Prob. 426 when the load P acts vertically...Ch. 4.2 - The observation cage C has a weight of 250 kip and...Ch. 4.2 - The steel bar has the original dimensions shown in...Ch. 4.2 - The ball is truncated at its ends and is used to...Ch. 4.5 - The column is constructed from high-strength...Ch. 4.5 - The column is constructed from high-strength...Ch. 4.5 - The A-36 steel pipe has a 6061-T6 aluminum core....Ch. 4.5 - If column AB is made from high strength precast...Ch. 4.5 - If column AB is made from high strength precast...Ch. 4.5 - Determine the support reactions at the rigid...Ch. 4.5 - If the supports at A and C are flexible and have a...Ch. 4.5 - The load of 2000 lb is to be supported by the two...Ch. 4.5 - The load of 2000 lb is to be supported by the two...Ch. 4.5 - The A-36 steel pipe has an outer radius of 20 mm...Ch. 4.5 - The 10-mm-diameter steel bolt is surrounded by a...Ch. 4.5 - The 10-mm-diameter steel bolt is surrounded by a...Ch. 4.5 - The assembly consists of two red brass C83400...Ch. 4.5 - The rigid beam is supported by the three suspender...Ch. 4.5 - The bolt AB has a diameter of 20 mm and passes...Ch. 4.5 - If the gap between C and the rigid wall at D is...Ch. 4.5 - The support consists of a solid red brass C83400...Ch. 4.5 - If there are n fibers, each having a...Ch. 4.5 - The rigid bar is pinned at A and supported by two...Ch. 4.5 - The rigid bar is pinned at A and supported by two...Ch. 4.5 - The rigid bar is pinned at A and supported by two...Ch. 4.5 - The rigid bar is pinned at A and supported by two...Ch. 4.5 - The 2014-T6 aluminum rod AC is reinforced with the...Ch. 4.5 - The 2014-T6 aluminum rod AC is reinforced with the...Ch. 4.5 - The three suspender bars are made of A992 steel...Ch. 4.5 - The three A-36 steel wires each have a diameter of...Ch. 4.5 - The A-36 steel wires AB and AD each have a...Ch. 4.5 - The post is made from 6061-T6 aluminum and has a...Ch. 4.5 - The post is made from 6061-T6 aluminum and has a...Ch. 4.5 - The bracket is held to the wall using three A-36...Ch. 4.5 - The bracket is held to the wall using three A-36...Ch. 4.5 - If each of the posts has an unloaded length of 1 m...Ch. 4.5 - The rigid bar is supported by the two short white...Ch. 4.5 - The assembly consists of two posts AB and CD each...Ch. 4.5 - The assembly consists of two posts AB and CD each...Ch. 4.5 - The assembly consists of two posts AB and CD each...Ch. 4.5 - The wheel is subjected to a force of 18 kN from...Ch. 4.6 - The C83400-red-brass rod AB and 2014-T6- aluminum...Ch. 4.6 - The assembly has the diameters and material...Ch. 4.6 - The rod is made of A992 steel and has a diameter...Ch. 4.6 - The two cylindrical rod segments are fixed to the...Ch. 4.6 - The two cylindrical rod segments are fixed to the...Ch. 4.6 - The pipe is made of A992 steel and is connected to...Ch. 4.6 - The bronze C86100 pipe has an inner radius of 0.5...Ch. 4.6 - The 40-ft-long A-36 steel rails on a train track...Ch. 4.6 - The device is used to measure a change in...Ch. 4.6 - The bar has a cross-sectional area A, length L,...Ch. 4.6 - When the temperature is at 30C, the A-36 steel...Ch. 4.6 - When the temperature is at 30C, the A-36 steel...Ch. 4.6 - When the temperature is at 30C, the A-36 steel...Ch. 4.6 - The 50-mm-diameter cylinder is made from Am...Ch. 4.6 - The 50-mm-diameter cylinder is made from Am...Ch. 4.6 - The wires AB and AC are made of steel, and wire AD...Ch. 4.6 - The cylinder CD of the assembly is heated from T1...Ch. 4.6 - The cylinder CD of the assembly is heated from T1=...Ch. 4.6 - The metal strap has a thickness t and width w and...Ch. 4.9 - Determine the maximum normal stress developed in...Ch. 4.9 - If the allowable normal stress for the bar is...Ch. 4.9 - The steel bar has the dimensions shown. Determine...Ch. 4.9 - The A-36 steel plate has a thickness of 12 mm. If...Ch. 4.9 - Determine the maximum axial force P that can be...Ch. 4.9 - Determine the maximum normal stress developed in...Ch. 4.9 - The member is to be made from a steel plate that...Ch. 4.9 - The resulting stress distribution along section AB...Ch. 4.9 - The resulting stress distribution along section AB...Ch. 4.9 - Prob. 4.96PCh. 4.9 - The weight is suspended from steel and aluminum...Ch. 4.9 - The bar has a cross-sectional area of 0.5 in2 and...Ch. 4.9 - The distributed loading is applied to the rigid...Ch. 4.9 - The distributed loading is applied to the rigid...Ch. 4.9 - The rigid lever arm is supported by two A-36 steel...Ch. 4.9 - The rigid lever arm is supported by two A-36 steel...Ch. 4.9 - The 300-kip weight is slowly set on the top of a...Ch. 4.9 - The rigid beam is supported by three 25-mm...Ch. 4.9 - The rigid beam is supported by three 25-mm...Ch. 4.9 - The rigid beam is supported by the three posts A,...Ch. 4.9 - The rigid beam is supported by the three posts A,...Ch. 4.9 - The bar having a diameter of 2 in. is fixed...Ch. 4.9 - Determine the elongation of the bar in Prob.4108...Ch. 4.9 - The rigid beam is supported by three A-36 steel...Ch. 4 - The assembly consists of two A992 steel bolts AB...Ch. 4 - The assembly shown consists of two A992 steel...Ch. 4 - The rods each have the same 25-mm diameter and...Ch. 4 - Two A992 steel pipes, each having a...Ch. 4 - The force P is applied to the bar, which is made...Ch. 4 - The 2014-T6 aluminum rod has a diameter of 0.5 in....Ch. 4 - The 2014-T6 aluminum rod has a diameter of 0.5 in....Ch. 4 - The rigid link is supported by a pin at A and two...Ch. 4 - The joint is made from three A992 steel plates...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- using the theorem of three moments, find all the reactions and supports, I need concise calculations only. the answers are at the bottom, I need concise steps and minimal explanationsarrow_forwardIn an industrial facility, a counter-flow double-pipe heat exchanger uses superheated steam at a temperature of 155°C to heat feed water at 30°C. The superheated steam experiences a temperature drop of 70°C as it exits the heat exchanger. The water to be heated flows through the heat exchanger tube of negligible thickness at a constant rate of 3.47 kg/s. The convective heat transfer coefficient on the superheated steam and water side is 850 W/m²K and 1250 W/m²K, respectively. To account for the fouling due to chemical impurities that might be present in the feed water, assume a fouling factor of 0.00015 m² K/W for the water side. The specific heat of water is determined at an average temperature of (30+70)°C/2 = 50°C and is taken to be Cp J/kg-K. Water Steam Determine the heat exchanger area required to maintain the exit temperature of the water to a minimum of 70°C. The heat exchanger area required isarrow_forwardStress, ksi 160 72 150- 140 80 70 ༄ ྃ ༈ ཎྜ རྦ ༅ ཎྜ ྣཧྨ ➢ 130 120 110 100 90 2.0 2.8 3.6 4.4 5 Wire diameter, mm 6.0 6.8 2 7.6 8.4 Compression and extension springs. ASTM A227 Class II Light service Average service 0.020 0.060 0.100 0.140 0.180 0.220 0.260 0.300 0.340 0.380 0.420 0.460 0.500 Wire diameter, in Torsional stress due to initial tension, ksi 10 ४ 20 Preferred range 100 Stress, MPa 9.2 10.0 10.8 11.6 12.4 1100 1035 965 895 825 760 Severe service 690 620 550 50 150 3456789 10 11 12 13 14 15 16 Spring index, C = DJD FIGURE 18-21 Recommended torsional shear stress in an extension spring due to initial tension (Data from Associated Spring, Barnes Group, Inc.) 50 200 485 Stress, MPaarrow_forward
- Bolted Joint Design Bolted Frames Total Force due to door weight: P = 240 lb Number of Bolts: N = Distance to Bolt C/L: a = 4 N/A Bolt Material - Allowable shear stress of bolt material: T₂ = x Distance from Bolt centroid to bolt: x = y Distance from Bolt centroid to bolt: y = Degrees per Radian- Results y-Load on each bolt: F, = Moment resisted by bolt pattern: M = Radial distance from Bolt centroid to bolt: r = Sum squares of all radial distances: Σr² Force on each bolt to resist moment: F, - Angle for force composition: e= X-Force on each bolt to resist moment: F- y-Force on each bolt to resist moment: Fly Total y-Force on each bolt: Fy = Resultant force on bolt 1: R₁ = Required shear stress area for a bolt: A₂ = ASTM Grade A307 Steel 10,000 0 psi from Table 20-1 3.0 57.296 in degrees lb per bolt lb-in Formula FS-P/N M-Px XB r = (x² + y²)0.5 in² Σ 4r² Mr F₁ = Στ lb degrees lb lb lb Minimum Bolt Diameter: Din = Rounded up Bolt Diameter: D = 55 P. 1.5 in 2 in (3x) 1 in This bracket…arrow_forwardUniversity of Babylon Collage of Engineering/ Al-Musayab Department of Automobiles Final Examination/ Stage: 3rd Notes: Answer 4 questions only 2023-2202 Subject: Theory of vehicles Date: 2023\06\10-Saturday Time: Three Hours Course 2nd Attempt 1st Q1: A Hooke's coupling connects two shafts whose axes are inclined at 30°. The of the driven shaft? Find the maximum value of retardation or acceleration and driving shaft rotates uniformly at 600 rpm. What are the extreme angular velocities state the angle where both will occur. (12.5 Marks) Q2: Four masses, A, B, C, and D), revolve at equal radii and are equally spaced along a shaft. The mass B is 7 kg, and the radius of C and D make angles of 90° and 240°, respectively, with the radius of B. Find the magnitude of the masses A, C, and D and the angular position of A so that the system may be completely balanced. (12.5 Marks) Q3: A cam has straight worked faces that are tangential to a base circle of diameter 90 mm. The follower is a roller…arrow_forwardProblem 18-26 Added Extension Springs Spring Material ASTM A227 Modulus of Elasticity of the Material in Shear: G 1.150E+07 psi Average Service Max Operating Load: F₁ = 100 lb Max Length between attachment points: L₁ = 60.00 in 20.00 lb 26.00 1.400 Min Operating Load: F₁ = Min Length between attachment points: L₁ = Maximum Outside Diameter = in in Results Note: you select a wire diameter from the "US steel wire gage" column in table 18-2 Formula k = AF/AL k = (F0-F1)/(Lo - L₁) Spring Rate: k = lb/in Assumed Trial Outside Diameter: OD = Assumed Trial Mean: D ma Assumed Design Stress in Spring: Tda in 1.070 in 102,000 psi Assumed Wahl Factor: K = 1.2 Calculated Wire Diameter: Dwa Actual Wire Diameter: Dw Actual outer diameter: OD = Actual inner diameter: ID= Spring Index: C = See Figure 18-8 Dw= [8KF Dm πTd 1/3 in 5' 5' 5' 5' This corresponds to US Steel 9 wire gage ID = Dm - Dw C = Dm/Dw 4C - 1 0.615 K = + 4C - с Wahl Factor: K = 8KFDm 8KFC T = TD πD Stress in Spring at F = Fo: To psi…arrow_forward
- CHAIN DRIVE DESIGN Initial Input Data: Application: Garage Door Opener Drive type: AC Motor Driven machine Chain and Sprocket to pull the door up Degrees per Radian: 57.2958 degrees Sprocket Diameter: D = 1.690 in Number of strands: Chain number: 1 40 Service factor: 1.3 Table 7-10 No. of teeth Computed Data: Actual Motor Power Input: 0.000 hp Sprocket Speed (for sprocket attached to gear shaft) Design power: 0.00 rpm 0 hp 11 12 0.06 0.15 0.29 0.56 0.99 1.09 1.61 2.64 TABLE 7-7 Horsepower Ratings-Single Strand Roller Chain No. 40 0.500 inch pitch 10 25 50 100 180 200 300 500 700 900 1000 1: 0.06 0.14 0.27 0.52 0.91 1.00 1.48 2.42 3.34 4.25 4.70 ! 3.64 4.64 5.13 13 0.07 0.16 0.31 0.61 1.07 1.19 1.75 2.86 3.95 5.02 5.56 Design Decisions-Chain Type and Teeth Numbers: 14 Chain number: Use Table 7-7 Chain pitch: p = in 15 Number of Teeth: N = Per Table 7-7 16 0.08 0.20 0.39 0.75 1.32 1.46 2.15 3.52 0.07 0.17 0.34 0.66 1.15 1.28 1.88 3.08 0.08 0.19 0.36 0.70 1.24 1.37 2.02 3.30 4.55 5.80…arrow_forwardInput Data: Torque needed to overcome rolling friction in rollers, slides and other moving parts, except for Motor and Worm Gear the worm gear T₁ = Length of travel of door: Time for door to open or close: LD = 50 lb-in. 90 in t= 12.5 seconds Pitch diameter for chain sprocket: DPC 1.690 in Weight of Door: P = No. of worm threads: Nw = Worm Pitch diameter: Dw Diametral pitch: Pd Normal pressure angle: Degrees per Radian: Number of gear teeth: Calculated Data: Linear velocity of door and chain (in/sec): Linear velocity of door and chain (ft/min): Output Speed of Gear and Sprocket: Upward Force due to Weight of Door: Фо = = NG= 240 lb 2 1.250 in 12 14.5 degrees 57.2958 degrees 28 Vα= in/sec VC= ft/min NG = rpm FD lb Net Upward Force on Door: Fou lb Torque on gear ignoring rolling friction: TG = lb-in. Formula = FDU FD-2 x Fo (note: Fo is the Max Operating load of the extension springs). This is also the initial tension in the chain. TG = FDU X DPC/2 This is the also the torque on the…arrow_forwardQ5/A: A car with a track of 1.5 m and a wheelbase of 2.9 m has a steering gear mechanism of the Ackermann type. The distance between the front stub axle pivots is 1.3 m. The length of each track arm is 150 mm, and the length of the track rod is 1.2 m. Find the angle turned through by the outer wheel if the angle turned through by the inner wheel is 30°. (6 Marks) Q5/B: Write True on the correct sentences and False on the wrong sentences listed below:- 1- In automobiles, the power is transmitted from the gearbox to the differential through bevel gears. 2- The minimum radius circle drawn to the cam profile is called the base circle. 3- The Proell governor, compared to the Porter governor, has less lift at the same speed. 4- The balancing of rotating and reciprocating parts of an engine is necessary when it runs at a slow speed. (6.5 Marks) ***Best of Luck *** جامعة بابل UNIVERSITY OF BABYLON Examiner: Mohanad R. Hameed Head of Department: Dr. Dhyai H. Jawadarrow_forward
- University of Babylon Collage of Engineering/ Al-Musayab Department of Automobiles Mid Examination/ Stage: 3rd Subject: Theory of Vehicles Date: 14 \ 4 \2025 Time: 1.5 Hours 2025-2024 Q1: The arms of a Porter governor are 250 mm long. The upper arms are pivoted on the axis of revolution, but the lower arms are attached to a sleeve at a distance of 50 mm from the axis of rotation. The weight on the sleeve is 600 N and the weight of each ball is 80 N. Determine the equilibrium speed when the radius of rotation of the balls is 150 mm. If the friction is equivalent to a load of 25 N at the sleeve, determine the range of speed for this position. Q2: In a loaded Proell governor shown in Figure below each ball weighs 3 kg and the central sleeve weighs 25 kg. The arms are of 200 mm length and pivoted about axis displaced from the central axis of rotation by 38.5 mm, y=238 mm, x=303.5 mm, CE 85 mm, MD 142.5 mm. Determine the equilibrium speed. Fe mg E M 2 Q3: In a spring loaded Hartnell type…arrow_forwardusing the theorem of three moments, find all the reactions and supports, I need the calculations onlyarrow_forwardQ.5: (10 Marks) Select the correct answer (choose 10 only) 1. The forward whirling speed is ......... the static structure tilting speed. (a) Less than (b) Higher than (c) equal to 2. The divergence between the forward and backward whirling speeds increases as: (a) The rotating speed increase (b) the polar moment of inertia increases (c) Both (a) and (b) (d) do not change 3. Increasing the system natural frequency can be done by: (a) add masses (b) adding braces and supports (c) increase damping 4. The amplitude of vibration due to external force can be reduced by: (a) Increasing damping (b) Decreasing damping (c) Increasing mass 5. Tuned absorbers are used to: (a) Shift the natural frequency (b) increase damping (c) Increase stiffness 6. Accelerometers sensors contains: г (a) Piezoelectric materials (b) Magnet and coil (c) coil only 7. Increasing the stiffness of the system causes: (a) Less transmitted force (b) more transmitted force (c) Transmitted force does not change 8. The…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning

Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
EVERYTHING on Axial Loading Normal Stress in 10 MINUTES - Mechanics of Materials; Author: Less Boring Lectures;https://www.youtube.com/watch?v=jQ-fNqZWrNg;License: Standard YouTube License, CC-BY