The reason why the given compound A has two stereoisomers and compound B, C exist as single compound has to be explained. Concept introduction: Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers. Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups. If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place. So stereoisomers will not exist. The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2 n , in which ‘n’ is the number of asymmetric centers.

Question

Want to see the full answer?

Answer 1

Question

Chapter 4.16, Problem 63P

Interpretation Introduction

Interpretation:

The reason why the given compound A has two stereoisomers and compound B, C exist as single compound has to be explained.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers.

Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups.

If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place. So stereoisomers will not exist.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Using the Nernst equation to calculate nonstandard cell voltage A galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction: MnO2 (s)+4H* (aq)+2Cr²+ (aq) → Mn²+ (aq)+2H₂O (1)+2Cr³+ (aq) + 2+ 2+ 3+ Suppose the cell is prepared with 7.44 M H* and 0.485 M Cr²+ in one half-cell and 7.92 M Mn² and 3.73 M Cr³+ in the other. Calculate the cell voltage under these conditions. Round your answer to 3 significant digits. ☐ x10 μ Х 5 ? 000 日。

Calculating standard reaction free energy from standard reduction... Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG° for the following redox reaction. Be sure your answer has the correct number of significant digits. NO (g) +H₂O (1) + Cu²+ (aq) → HNO₂ (aq) +H* (aq)+Cu* (aq) kJ - ☐ x10 x10 olo 18 Ar

Calculating the pH of a weak base titrated with a strong acid b An analytical chemist is titrating 116.9 mL of a 0.7700M solution of aniline (C6H5NH2) with a 0.5300M solution of HNO3. The pK of aniline is 9.37. Calculate the pH of the base solution after the chemist has added 184.2 mL of the HNO 3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places. pH = ☐ ☑ 5