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Concept explainers
Interpretation:
The given compound has to be drawn in perspective formula.
Concept introduction:
Perspective formula: draw two bonds of asymmetric carbon is in plane, one bond as a solid wedge that coming out of plane and the fourth bond as hatched wedge that pointing away from the plane. The solid wedge is always below to the hatched wedge.
Fischer projections: the asymmetric center (carbon) represents as the point of intersection of two perpendicular lines, in which the horizontal lines represent the bonds that project out of the plane of the paper and the vertical lines represent the bonds that away from the plane of the paper.
According to Cahn-Ingold-Prelog system,
The group attached to asymmetric center should be ranked based on the
Stereoisomer is named by following Cahn-Ingold-Prelog system, in which R or S letter is used to differentiate between enantiomers.
For Fischer projection formula: Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is bonded in horizontal line, then the configuration is assigned as just reverse.
For perceptive formula: Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.
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Chapter 4 Solutions
Organic Chemistry (8th Edition)
- [In this question, there are multiple answers to type in a "fill-in-the-blank" fashion - in each case, type in a whole number.] Consider using Slater's Rules to calculate the shielding factor (S) for the last electron in silicon (Si). There will be electrons with a 0.35 S-multiplier, electrons with a 0.85 S-multiplier, and electrons with a 1.00 S-multiplier.arrow_forwardProvide the unknown for the given data.arrow_forwardDraw the Lewis structures of two methanol (CH3OH) molecules and depict hydrogenbonding between them with dashed lines. Show all lone pairs. Provide a thorough analysis to apply concept idea into other problems.arrow_forward
- Steps and explanation please.arrow_forwardHow could you distinguish between each pair of compounds below using IR? For each pair citeone bond and it’s frequency that you could use to distinguish between them. Please provide thorough analysis to apply into further problems.arrow_forwardSteps and explanation please.arrow_forward
- Provide the unknown for the given dataarrow_forwardProvide the unknown for the given data.arrow_forwardElectron Arrangement A. Fill in the following chart relating to levels, sublevels and orbitals. Levels (n) 1 Sublevels # of Orbitals per sublevel 2 3 4 # of Electrons per sublevel Total Electrons per level Complete: B. Answer the following questions related to levels, sublevels, orbitals and electrons. 1. How many sublevels are in energy level 2? 2. How many orbitals are in a 4f sublevel? 3. How many electrons can level 3 hold? 4. How many orbitals are in level 4? 5. How many electrons can sublevel 2p hold? 11arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
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