Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Question
Chapter 4, Problem 8RQ
To determine
Distinguish between “eutectic” and “eutectoid”?
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If a eutectoid steel sample is heated to 800°C and then quenched in a cold-water bath then
what would be the possible microstructure? Draw the microstructure and label it.
Pls do it 30min
An eutectoid steel is cooled slowly from 1000 °C to room temperature by the following different cooling rates:
(i) 1 °C/s,
(ii) 20 °C/s,
(iii) 50 °C/s,
(iv) 175 °C/s.
Name the respective microstructural products for the above four cooling rates.
Excellent combinations of hardness, streneth, and toughness are obtained from
bainite. One heat treater austenitized a eutectoid steel at 750°C, quenched and
haid the steal at 250°C for 15 min, and finaly permitted the staal to cool to
room temperature. Did he produce the required bainitic structure? Use the
diegram below in your answer
Answer:
Tie
ReckvellChndre
Chapter 4 Solutions
Manufacturing Engineering & Technology
Ch. 4 - Describe the difference between a solute and a...Ch. 4 - What is a solid solution?Ch. 4 - Prob. 3RQCh. 4 - Describe the difference between a single-phase and...Ch. 4 - What is an induction heater? What kind of part...Ch. 4 - Describe the major features of a phase diagram.Ch. 4 - What do the terms equilibrium and constitutional,...Ch. 4 - Prob. 8RQCh. 4 - What is tempering? Why is it performed?Ch. 4 - Explain what is meant by severity of quenching.
Ch. 4 - What are precipitates? Why are they significant in...Ch. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - You may have seen some technical literature on...Ch. 4 - Prob. 17QLPCh. 4 - What is the difference between hardness and...Ch. 4 - Prob. 19QLPCh. 4 - Prob. 20QLPCh. 4 - Prob. 21QLPCh. 4 - Describe the characteristics of (a) an alloy, (b)...Ch. 4 - Explain why carbon, among all elements, is so...Ch. 4 - Prob. 24QLPCh. 4 - In Section 4.8.2, several fluids are listed in...Ch. 4 - Why is it important to know the characteristics of...Ch. 4 - Explain why, in the abscissa of Fig. 4.16c, the...Ch. 4 - Prob. 28QLPCh. 4 - Prob. 29QLPCh. 4 - Prob. 30QLPCh. 4 - Design a heat-treating cycle for carbon steel,...Ch. 4 - Using Fig. 4.4, estimate the following quantities...Ch. 4 - Prob. 33QTPCh. 4 - Prob. 34QTPCh. 4 - Prob. 35SDPCh. 4 - Figure 4.18b shows hardness distributions in...Ch. 4 - Throughout this chapter, you have seen specific...Ch. 4 - Refer to Fig. 4.24, and think of a variety of...Ch. 4 - Inspect various parts in your car or home, and...
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- Comparison of treatment processes (annealing, normalizing, hardening and tempering) according to heating and cooling, microstructure and mechanical propertiesarrow_forwardExplain annealing process?arrow_forwardWrite the materials by low ductility to increased ductility: *steels are assumed to have no cold work and contain equilibrium phases* (Diamond, 1040 steel, 1040 steel with 10% cold work, pure copper, polymer)arrow_forward
- Use the following TTT Diagram for the following questions: 800 A 1400 -Eutectoid temperature 700 1200 600 1000 500 800 400 600 300 Mistart) 200 50% 400 M+A M(50%) M(90%) 100 200 10-1 10 102 103 10 105 Time (s) Temperature ("C) Termperature (°F)arrow_forwardMaterials Science Engineering; CCT Diagramarrow_forwardUsing the TTT diagram, what microstructure would be developed by rapidly cooling to 650°C and holding for 50 seconds, followed by rapid cooling to 500°C and holding for 5 seconds, followed by quenching to room temperature? (give relative percentages of each microstructure component) Using the TTT diagram, describe the entire thermal treatment that would generate a microstructure consisting of 50% bainite, and 50% martensite. On the CCT diagram to the right, what microstructure would be developed by following cooling curve (c), then heating to 700°C for at least a day? Temperature l"C)arrow_forward
- Answer this please importantarrow_forwardTo increase the hardness of a steel gear, it was carburized at 850oC by introducing 1.3%C at its steel surface. What will be the final carbon content 1.4 mm beneath the surface if this treatment was lasted for 26 hours. The initial carbon content of steel is 0.1%C. (gas constant is 8.31 j/mol.K)arrow_forwardWhat are some possible defects in drawn sheet-metal parts? In blanking of a circular sheet-metal part, is the clearance applied to the punch diameter or the die diameter? What is martensite? Based on the TTT curve, what is it that should be avoided during martensitic process? What is the main condition for strengthening an alloy by precipitation?arrow_forward
- 1.0% of euctectoid carbon steel was slowly cooled from 900C to a temperature just below 723C 1. Calculate the wt% of cementite at the proeutectoid cementite 2. Calculate the amount of euctectoid cementitearrow_forward1. Why does the tensile strength of steel, which contains only austenite at room temperature, differ fromsteel that shows only pearlite in its microstructure? Give two important reasons for the difference. 2. What general prerequ_isites exist for the formation of martensite in steel? 3. What is an isothermal transformation of a material in the solid state condition? 4. Draw a typical isothermal transformation diagram for plain .carbon eutectoid steel and indicate thevarious decomposition products expected by simple diagrammatic drawing.arrow_forwardWhat is the microstructure that will be formed after heat treatment of steel containing 1.4 carbon ratio with normalization and air cooling? support with phase diagram and TTT diagrams.arrow_forward
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