Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 4, Problem 33QTP
(a)
To determine
Determine the time that it would take for 1080 steel to soften to
(b)
To determine
Determine the time that it would take for 1080 steel to soften to
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part made from AISI 1212 steel undergoes a 20 percent cold-work operation.
(a) Obtain the yield strength and ultimate strength before and after the cold-work operation. Determine
the percent increase in each strength.
(b) Determine the ratios of ultimate strength to yield strength before and after the cold work operation.
What does the result indicate about the change of ductility of the part?
A 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively.
Calculate the length of the sheet after the rolling operation in feet.
I need the answer as soon as possible
Chapter 4 Solutions
Manufacturing Engineering & Technology
Ch. 4 - Describe the difference between a solute and a...Ch. 4 - What is a solid solution?Ch. 4 - Prob. 3RQCh. 4 - Describe the difference between a single-phase and...Ch. 4 - What is an induction heater? What kind of part...Ch. 4 - Describe the major features of a phase diagram.Ch. 4 - What do the terms equilibrium and constitutional,...Ch. 4 - Prob. 8RQCh. 4 - What is tempering? Why is it performed?Ch. 4 - Explain what is meant by severity of quenching.
Ch. 4 - What are precipitates? Why are they significant in...Ch. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - You may have seen some technical literature on...Ch. 4 - Prob. 17QLPCh. 4 - What is the difference between hardness and...Ch. 4 - Prob. 19QLPCh. 4 - Prob. 20QLPCh. 4 - Prob. 21QLPCh. 4 - Describe the characteristics of (a) an alloy, (b)...Ch. 4 - Explain why carbon, among all elements, is so...Ch. 4 - Prob. 24QLPCh. 4 - In Section 4.8.2, several fluids are listed in...Ch. 4 - Why is it important to know the characteristics of...Ch. 4 - Explain why, in the abscissa of Fig. 4.16c, the...Ch. 4 - Prob. 28QLPCh. 4 - Prob. 29QLPCh. 4 - Prob. 30QLPCh. 4 - Design a heat-treating cycle for carbon steel,...Ch. 4 - Using Fig. 4.4, estimate the following quantities...Ch. 4 - Prob. 33QTPCh. 4 - Prob. 34QTPCh. 4 - Prob. 35SDPCh. 4 - Figure 4.18b shows hardness distributions in...Ch. 4 - Throughout this chapter, you have seen specific...Ch. 4 - Refer to Fig. 4.24, and think of a variety of...Ch. 4 - Inspect various parts in your car or home, and...
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- A 10-mm-diameter Brinell hardness indenter produced an indentation of 1.52 mm in diameter in a steel alloy when a load of 500 kg was used. (a) Compute the HB of this material. (b) What will be the diameter of an indentation to yield a hardness of 400 HB when a 500-kg load is used?arrow_forwardName the material's strengthening mechanism behind each of the following phenomena: (1) Si alloyed aluminum alloy has a higher strength than pure aluminum metal. (2) A steel gains extra strength after cold rolling. Blank # 1 Blank # 2arrow_forwardA part made from hot-rolled AISI 1212 steel undergoes a certain amount of cold-work operation. If the ultimate strength of the material after cold work operation was 80 kpsi. (a) Determine the percentage of cold work (b) Obtain the yield strength after the cold work (c) Determine the hardness of the material before and after the cold work operationarrow_forward
- A mild steel specimen is given to you which has a tensile strength of 40MPA and your main objective is to increase its strength. What type of heat treatment would you recommend? Justify your answer with proper reasoning.arrow_forwardWhen a 3000 kg load is applied to a 10-mm-diameter ball in a Brinell test of a steel,an indentation of 3.1 mm diameter is produced.Estimate the tensile strength of the steel?arrow_forwardI need correct neat and clean handwritten solution. I will surely upvotearrow_forward
- The lower yield point for a certain plain carbon steelbar is found to be 135 MPa, while a second bar of the samecomposition yields at 260 MPa. Metallographic analysisshows that the average grain diameter is 50μm in the firstbar and 8μm in the second bar.a. Predict the grain diameter needed to cause a loweryield point of 205 MPa.b. If the steel could be fabricated to form a stablegrain structure of 500 nm grains, what strengthwould be predicted?c. Why might you expect the upper yield point to bemore alike in the first two bars than the lower yieldpoint?arrow_forwardSuppose a 24 in. long round bar is to support a load of 400 lb. without any permanent deformation. Calculate the minium diameter of the bar if it is made of (a) AZ0A-T5 magnesium alloy and (b) 6061-T6 aluminum alloy. Calculate the wieght of the bar and the approximate cost based on pure Al and Mg in each case.arrow_forward5. (i) A 10-mm-diameter Brinell hardness indenter produced an indentation 2.50 mm in diameter in a steel alloy when a load of 1000 kg was used. Compute the HB of this material. (ii) What will be the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used?arrow_forward
- A 2.0-inch diameter 4140 steel bar is austenized and tempered in oil without Agitation, determine the resulting hardness at 0.6 inches below the surface, present all the Procedure to arrive at the answer (include sketch of the piece and graph used with steps Using word forms)arrow_forwardA sheet of a 70% Cu-30% Zn alloy is cold-rolled 20% to a thickness of 3.0mm. The sheet is then further coldrolledto 2.0 mm. What is the percentage cold work?arrow_forwardA batch of casted mild steel has a modulus of elasticity of 200 GPa and a yield strength of 250MPa. Calculate for its modulus of resilience. After cold working the steel, the yield strength increases to 310 MPa. Calculate for the percent reduction in the average grain diameter given σo =70 MPa and k = 0.74.arrow_forward
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