Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Textbook Question
Chapter 4, Problem 16QLP
You may have seen some technical literature on products stating that certain parts in those products are “heat treated.” Describe briefly your understanding of this term and why the manufacturer includes it.
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Heat treatment is the controlled heating and cooling of metals to alter their physical and mechanical properties without changing the product shape. When performing the cooling step of the tempering process, knife makers have used material such as clay to cover portions of the blade to slow the cooling rate of the covered steel. Why may this technique be beneficial for making a sword which holds a sharp edge while remaining flexible enough to withstand the forces subjected to it in battle?
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Does consideration of creep become important when materials are in service for long periods of time?
Chapter 4 Solutions
Manufacturing Engineering & Technology
Ch. 4 - Describe the difference between a solute and a...Ch. 4 - What is a solid solution?Ch. 4 - Prob. 3RQCh. 4 - Describe the difference between a single-phase and...Ch. 4 - What is an induction heater? What kind of part...Ch. 4 - Describe the major features of a phase diagram.Ch. 4 - What do the terms equilibrium and constitutional,...Ch. 4 - Prob. 8RQCh. 4 - What is tempering? Why is it performed?Ch. 4 - Explain what is meant by severity of quenching.
Ch. 4 - What are precipitates? Why are they significant in...Ch. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - You may have seen some technical literature on...Ch. 4 - Prob. 17QLPCh. 4 - What is the difference between hardness and...Ch. 4 - Prob. 19QLPCh. 4 - Prob. 20QLPCh. 4 - Prob. 21QLPCh. 4 - Describe the characteristics of (a) an alloy, (b)...Ch. 4 - Explain why carbon, among all elements, is so...Ch. 4 - Prob. 24QLPCh. 4 - In Section 4.8.2, several fluids are listed in...Ch. 4 - Why is it important to know the characteristics of...Ch. 4 - Explain why, in the abscissa of Fig. 4.16c, the...Ch. 4 - Prob. 28QLPCh. 4 - Prob. 29QLPCh. 4 - Prob. 30QLPCh. 4 - Design a heat-treating cycle for carbon steel,...Ch. 4 - Using Fig. 4.4, estimate the following quantities...Ch. 4 - Prob. 33QTPCh. 4 - Prob. 34QTPCh. 4 - Prob. 35SDPCh. 4 - Figure 4.18b shows hardness distributions in...Ch. 4 - Throughout this chapter, you have seen specific...Ch. 4 - Refer to Fig. 4.24, and think of a variety of...Ch. 4 - Inspect various parts in your car or home, and...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- As a materials engineer in a metal-processing company, you are given a section of metal to heat treat after cold working. You are also able to view the microstructure of the metal before and after heat treatment and characterise its mechanical properties. Which of the following describes what you expect to find, when comparing the properties of the metal after heat treatment to before? Select one or more: a. Increased strength b. Reduced strength □ C. Increased ductility d. Reduced ductilityarrow_forwardQ1 Contrast poly-crystalline silicon solar cells, GaAs solar cells, copper indium di-selenide solar cells, and cadmium telluride solar cells with respect to the type of material, the physical configuration of the device and its working principle. [Please note that the answer must be written in your own words, in full sentences. It would be advisable to include diagrams in your answer to depict physical configurations. Do not forget to reference your sources.]arrow_forwardeffect of the cooling rate on the microstructure and hardness of a materialarrow_forward
- Advanced Physicswhat are the real life applications of cold working and annealing?arrow_forwardThe Allocated alloys are (i) Alloy : Udimet 720 (ii) Technical ceramic : Boron nitride (iii) Polymer/elastomer : Polycarbonate | Question 6 Ta) Explain the microstructural changes that your allocated alloy exhibits during age Thardening. You should use a sketch the microstructure of your material (i) held for 30 I minutes at the solution temperature, (ii) after, subsequently, cooling rapidly from the |solution temperature to room temperature, (ii) after, subsequently, holding at the commercial aging temperature for the prescribed time, to support your explanation. I b) Compare and contrast how precipitates (i) increase the yield strength of some alloys at room temperature, and (i) lower the creep rate of some alloys at elevated temperature. Ic) Your allocated alloy is strengthened by intermetallic precipitates that grow during aging. By both defining an intermetallic and detailing those found in your alloy, explain | why they are so effective at strengthening your material.arrow_forwardRegarding annealing, choose the right answer (One or more): The actual annealing time must be long enough to allow for any necessary transformation reactions that may occur Annealing can be performed to release internal stresses of the material The main purpose of annealing is to decrease or restore material's ductility Time isn't a significant parameter in annealing process If the rate of temperature change is too great, temperature gradients and internal stresses may be induced that may lead to warping or even crackingarrow_forward
- What is the advantage of nitriding? Select all correct answers. Some complex components can be nitride without difficulty. Better wear resistance. Better fatigue resistance. The cheapest method of case hardening. What is the correct definition of plastic deformation? The behavior of a material when its size changes by the addition of heat. The behavior of a material that deforms under load and returns to its original shape when the load is removed. Deformation caused by cleavage, where the material is actually pulled apart across atomic planes within the crystals or along the grain boundaries. The behavior of a material that deforms under load and does not fully return to its original shape when the load is removed.arrow_forward1. What is Gas Expansion? Discuss some applications whereby Gas Expansion is used in real life 2. What is the Effect of conductivity and Shape on Cooling? Discuss some applications whereby the Effect of conductivity and Shape on Cooling is used in real life. 3. What is Heat Capacity of a material? Discuss some applications whereby Heat Capacity of a material is used in real life.arrow_forwardManufacturing Processes What are the different types of heat treatments? Write a detailed note on each type. How can Mechanical Properties be improved using each heat treatment?arrow_forward
- Question 4 A continuous 20meter long cable tray must be installed in an aircraft compartment. The tray must combine high strength, lightweight and must be electrical insulating. Which class of material would you suggest and which manufacturing process to manufacture this cable tray component? You should justify your material and process selections.arrow_forwardYou're an engineer working for a land-based gas turbine manufacturer. These turbines are similar to jet engines, but they are used onshore to provide power for power generation and gas compression pipeline applications. Operation of motor a ceramic-based thermal barrier to turbine blades in the first stage turbine to increase its temperature and efficiency suppose you want to apply a coating. By making the necessary associations between process-structure-property-performance describe in detail the following options. a) What do engineers like when trying to design a ceramic coating to be applied to a super alloy metal blade can you face difficulties? b) what properties should be considered when choosing a suitable ceramic material for a coating?arrow_forwardSelect 3 principal driving forces for the development of mechanical properties during heat treatment. Group of answer choices: Microstructure Changes Formation of Surface Oxide Cooling Rate Ambient Temperature Heating Rate Diffusion Rate Heating Methodarrow_forward
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How to make metal stronger by heat treating, alloying and strain hardening; Author: Billy Wu;https://www.youtube.com/watch?v=7lM-Y4XndsE;License: Standard Youtube License