Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 4, Problem 25QLP
In Section 4.8.2, several fluids are listed in terms of their cooling capacity in quenching. Which physical properties of these fluids influence their cooling capacity?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Discuss the various stages in Quenching process with neat sketches.
1.Mention four quenchants and describe how each of them affect the strength of the material being quenched arranging them in a decending ordrer.
2. Draw a typical time temperature transformation diagram showing how a material is cooled under critical cooiling rate.
3. explain non equilibrium cooling
26.2. List the Objectives of Heat Treatment.
Chapter 4 Solutions
Manufacturing Engineering & Technology
Ch. 4 - Describe the difference between a solute and a...Ch. 4 - What is a solid solution?Ch. 4 - Prob. 3RQCh. 4 - Describe the difference between a single-phase and...Ch. 4 - What is an induction heater? What kind of part...Ch. 4 - Describe the major features of a phase diagram.Ch. 4 - What do the terms equilibrium and constitutional,...Ch. 4 - Prob. 8RQCh. 4 - What is tempering? Why is it performed?Ch. 4 - Explain what is meant by severity of quenching.
Ch. 4 - What are precipitates? Why are they significant in...Ch. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - You may have seen some technical literature on...Ch. 4 - Prob. 17QLPCh. 4 - What is the difference between hardness and...Ch. 4 - Prob. 19QLPCh. 4 - Prob. 20QLPCh. 4 - Prob. 21QLPCh. 4 - Describe the characteristics of (a) an alloy, (b)...Ch. 4 - Explain why carbon, among all elements, is so...Ch. 4 - Prob. 24QLPCh. 4 - In Section 4.8.2, several fluids are listed in...Ch. 4 - Why is it important to know the characteristics of...Ch. 4 - Explain why, in the abscissa of Fig. 4.16c, the...Ch. 4 - Prob. 28QLPCh. 4 - Prob. 29QLPCh. 4 - Prob. 30QLPCh. 4 - Design a heat-treating cycle for carbon steel,...Ch. 4 - Using Fig. 4.4, estimate the following quantities...Ch. 4 - Prob. 33QTPCh. 4 - Prob. 34QTPCh. 4 - Prob. 35SDPCh. 4 - Figure 4.18b shows hardness distributions in...Ch. 4 - Throughout this chapter, you have seen specific...Ch. 4 - Refer to Fig. 4.24, and think of a variety of...Ch. 4 - Inspect various parts in your car or home, and...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Enumerate and explain each briefly the FOUR (4) Properties of the Bernoulli Process.arrow_forwardIn welding of metals, molten metal is deposited between the two objects that are to be welded together. Most of the heat from the molten material is conducted into the area around the weld, significantly increasing the temperature in the area, which can affect the local material properties. This area is often called the Heat Affected Zone (HAZ). Assuming you have base metal that is hypereutectoid steel, with a Cementite+Fine Pearlite microstructure, estimate what the microstructure would be in Area 1 and Area 2 of the HAZ. What is the primary factor (other than temperature and composition) that would affect what type of microstructure would be created?arrow_forwardHeat treatment is the controlled heating and cooling of metals to alter their physical and mechanical properties without changing the product shape. When performing the cooling step of the tempering process, knife makers have used material such as clay to cover portions of the blade to slow the cooling rate of the covered steel. Why may this technique be beneficial for making a sword which holds a sharp edge while remaining flexible enough to withstand the forces subjected to it in battle?arrow_forward
- How would you use the principle measure the heat output of something? For design a setup that can be used to measure the heat output of an ironing press.arrow_forwardNi-W alloys are widely used in tape form, i.e., sheets that are a hundred microns thick and several hundred meters long. A. A starting sheet of Ni-W alloy cannot be cold-rolled into a tape in a single pass. Instead, cold-rolling steps must be alternated with annealing steps. Why? B. Consider a fully-annealed, 1 cm-thick, 1 m-long sheet which is cold-rolled to a 7-mm thickness. What is the %CW? Assuming that the width does not change, how long is the sheet after rolling? C. Now consider an identical starting sheet that is rolled to a 3-mm thickness. How do the yield strength, tensile strength, and ductility of this rolled sheet compare to the previous one? D. If the maximum amount of cold work that can be done in a work-annealing cycle is 70%CW, how many cycles are required to roll the Ni-W alloy sheet to a thickness of 50 μm?arrow_forwardManufacturing methodsarrow_forward
- describe the effect that tempering has on material propertiesarrow_forwardIt has been suggested that compared to SMAW, the cooling rate is higher in GMAW and it is, therefore, more likely for heat-affected zone cracking to occur in hardenable steels. What is the main reason for the cooling rate to be higher in GMAW than SMAW?arrow_forwardEnumerate and define the three types of heat treatment.arrow_forward
- Which of the following may occur during an annealing heat treatment? (Please choose all that apply) Stresses may be relieved Ductility may decrease Toughness may increase Strength may increasearrow_forward1, What does steel have in terms of hot and cold shortness? What led to the Titanic disaster (focus only on the materials engineering component of the disaster in your response)? 2. What are the remedies for steel that is too hot or too cold? Respond succinctly. 3. What does metals and alloys' hydrogen embrittlement entail? What is the cheapest way to prevent hydrogen embrittlement in metals and alloys?arrow_forwardExample Problem-2 A cylindrical rod of non cold-worked brass having an initial diameter of 6.4 mm (0.25 in.) is to be cold worked by drawing such that the cross-sectional area is reduced. It is required to have a cold-worked yield strength of at least 345 Mpa (50,000 psi) and a ductility in excess of 20%EL; in addition, a final diameter of 5.1 mm (0.20 in.) is necessary. Describe the solution.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...
Mechanical Engineering
ISBN:9781305494695
Author:Larry Jeffus
Publisher:Cengage Learning
Introduction to Ferrous and Non-Ferrous Metals.; Author: Vincent Ryan;https://www.youtube.com/watch?v=zwnblxXyERE;License: Standard Youtube License