Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Textbook Question
Chapter 4, Problem 22QLP
Describe the characteristics of (a) an alloy, (b) pearlite, (c) austenite, (d) martensite, and (e) cementite.
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wWucostuons ¢ 1. Differentiate between the following transformations Pearlite, (b) Bainitic (c) Martensitic, based on Diffusion, Temperature range, Nuclei, Kinetics of reaction, Crystallography, Density of dislocation, Surface relief, and Growth rate.
Chapter 4 Solutions
Manufacturing Engineering & Technology
Ch. 4 - Describe the difference between a solute and a...Ch. 4 - What is a solid solution?Ch. 4 - Prob. 3RQCh. 4 - Describe the difference between a single-phase and...Ch. 4 - What is an induction heater? What kind of part...Ch. 4 - Describe the major features of a phase diagram.Ch. 4 - What do the terms equilibrium and constitutional,...Ch. 4 - Prob. 8RQCh. 4 - What is tempering? Why is it performed?Ch. 4 - Explain what is meant by severity of quenching.
Ch. 4 - What are precipitates? Why are they significant in...Ch. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - You may have seen some technical literature on...Ch. 4 - Prob. 17QLPCh. 4 - What is the difference between hardness and...Ch. 4 - Prob. 19QLPCh. 4 - Prob. 20QLPCh. 4 - Prob. 21QLPCh. 4 - Describe the characteristics of (a) an alloy, (b)...Ch. 4 - Explain why carbon, among all elements, is so...Ch. 4 - Prob. 24QLPCh. 4 - In Section 4.8.2, several fluids are listed in...Ch. 4 - Why is it important to know the characteristics of...Ch. 4 - Explain why, in the abscissa of Fig. 4.16c, the...Ch. 4 - Prob. 28QLPCh. 4 - Prob. 29QLPCh. 4 - Prob. 30QLPCh. 4 - Design a heat-treating cycle for carbon steel,...Ch. 4 - Using Fig. 4.4, estimate the following quantities...Ch. 4 - Prob. 33QTPCh. 4 - Prob. 34QTPCh. 4 - Prob. 35SDPCh. 4 - Figure 4.18b shows hardness distributions in...Ch. 4 - Throughout this chapter, you have seen specific...Ch. 4 - Refer to Fig. 4.24, and think of a variety of...Ch. 4 - Inspect various parts in your car or home, and...
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- 9. Typical microscopic images of spheroidite, lower bainite and tempered martensite of an iron-carbon alloy are represented in the following images; 9.a) Briefly describe the microstructural difference between spheroidite and tempered martensite. 9.b) Explain why tempered martensite is much harder and stronger. 9.c) Briefly describe the microstructural difference between lower bainite and tempered martensite. Ferrite Cementite Do 05 μη lower bainite - carbides 0.5 μm tempred martensite - carbides in multiple directions 60 μη oriented in the same directionarrow_forwardWhat are the crystal structures for carbon steel and stainless steels?Name and describe 2 examples of crystal structures for each of the steels mentioned.If there are more than 3 crystal structures, they must be mentioned.arrow_forwardExplain why martensite is hard? What is the crystal structure of martensite? Show the positions of carbon atoms in unit cell of martensite.arrow_forward
- The density of pure aluminum calculatedfrom crystallographic data is expected tobe 2.69955 g cm3.(a) Design an aluminum alloy that has adensity of 2.6450 g cm3(b) Design an aluminum alloy that has adensity of 2.7450 g cm3. The density of pure aluminum calculatedfrom crystallographic data is expected tobe 2.69955 g cm3.(a) Design an aluminum alloy that has adensity of 2.6450 g cm3.(b) Design an aluminum alloy that has adensity of 2.7450 g cm3.arrow_forwardwWucsuons © 1. Differentiate between the following transformations Pearlite, (b) Bainitic (c) Martensitic, based on Diffusion, Temperature range, Nuclei, Kinetics of reaction, Crystallography, Density of dislocation, Surface relief, and Growth rate.arrow_forwardPlease don't provide handwritten solution .....arrow_forward
- Discuss under what circumstances martensite is formed and highlight its effect on mechanical properties.arrow_forward6. What are the 4 strategies for strengthening metals? Explain in detail. Do these 4 strategies work for all metals regardless of their crystallinity? Why or why not?arrow_forwardAnswer all the questions briefly 1. Define the term alloy and give an example. 2. Why is aluminum useful for aeroplane wings? 3. Why is cast iron useful for manhole covers? 4. Name the element that is added to iron to make mild steel. 5. Explain why copper might be suitable for the roof of a building.arrow_forward
- While there is about 2 times difference between tensile and compression strength in DD with spheroid graphite, there is about 3 times difference in DD with lamellar graphite. According to this: a) What is the reason for the difference between compressive and tensile strengths in cast irons? Please explain. b) Why is this difference much greater in lamellar graphite cast iron? Please explain. c) Write down the general properties of cast ironsarrow_forwardQuestion 3: Indicate which of the following microstructures corresponds to Pearlite Bainite Spheroidite_ Martensite What is the reason(s) behind your selection? (b) and Tempered Martensite (e) 10 μm 1 μm (d) 10 μπ 10 µmarrow_forwardWhich of the following alloys would form a complete substitutional solid solution? O Metal 1 is HCP, metal 2 is FCC, and atomic radius difference is less than 15%. O Metal 1 is BCC, metal 2 is BCC, and atomic radius difference is at least 15%. O Metal 1 is FCC, metal 2 is FCC, and atomic radius difference is 12%. O Metal 1 is BCC, metal 2 is FCC, and atomic radius difference is 12%. O Metal 1 is FCC, metal 2 is FCC, and atomic radius difference is 15%.arrow_forward
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