Problem 1. A 2m |P = 5kN q=3kN/m BY WW 2m C 3m This beam is only one time statically indeterminate and, thus, requires only one equation. Numbering the supports from 0, 1 and 2 we get MoL1 + 2M₁(L1 + L2) + M2L2 = −6 | 2M₁(4+3)= -6 (10.26.75-1.5) 3 A202 + L₁ L₂ t

Elements Of Electromagnetics
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Using the three moment theorem, how was A2 determined?

Problem 1.
A
2m
|P = 5kN
q=3kN/m
BY WW
2m
C
3m
This beam is only one time statically indeterminate and, thus, requires only one equation.
Numbering the supports from 0, 1 and 2 we get
MoL1 + 2M₁(L1 + L2) + M2L2 = −6 |
2M₁(4+3)= -6
(10.26.75-1.5)
3
A202
+
L₁
L₂
t
Transcribed Image Text:Problem 1. A 2m |P = 5kN q=3kN/m BY WW 2m C 3m This beam is only one time statically indeterminate and, thus, requires only one equation. Numbering the supports from 0, 1 and 2 we get MoL1 + 2M₁(L1 + L2) + M2L2 = −6 | 2M₁(4+3)= -6 (10.26.75-1.5) 3 A202 + L₁ L₂ t
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