HW3_4 The displacement, uy, along the simply supported beam shown below is given as x3 - (²) x² + (57) ₂ - (²) (x² − (x − 5) ¹) + x3 238.25x + (57): x3 - 238.25x − (²) (x² − (x − 5)¹) + 75(x − 7)² + − (5) (x² − (x − 5)¹) + 75(x − 7)² + (15) (x − 8)³ + (57) x Uy (x) = Plot this piecewise function. Use Newton-Raphson method to find the x location of the maximum displacement with 3 significant figures of accuracy. Print the answer to the screen using appropriate formatting. - 57 6 238.25x गणित 20 kips/ft x3 - 238.25x 150 kip-ft 0≤x≤5 5 < x≤7 7 < x≤8 8 ≤ x ≤ 10 15 kips TI

Elements Of Electromagnetics
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HW3_4 The displacement, uy, along the simply supported beam shown below is given as
x³
238.25x
57
6
- (²) x + + (5/7).
- (3) (x² - (x − 5) ¹) + x3
− (§) (x¹ − (x − 5)¹) + 75(x − 7)² +
− (5) (x² − (x − 5)¹) + 75(x − 7)² + + (15) (x − 8)³ +
57
x³
57
-
Uy (x) =
Plot this piecewise function. Use Newton-Raphson
method to find the x location of the maximum
displacement with 3 significant figures of accuracy.
Print the answer to the screen using appropriate
formatting.
mm
238.25x
238.25x
20 kips/ft
5'
x³ - 238.25x
150 kip-ft
0≤x≤5
5 < x≤7
7 < x≤8
8 < x≤ 10
15 kips
2'
7/7/7/7
Transcribed Image Text:HW3_4 The displacement, uy, along the simply supported beam shown below is given as x³ 238.25x 57 6 - (²) x + + (5/7). - (3) (x² - (x − 5) ¹) + x3 − (§) (x¹ − (x − 5)¹) + 75(x − 7)² + − (5) (x² − (x − 5)¹) + 75(x − 7)² + + (15) (x − 8)³ + 57 x³ 57 - Uy (x) = Plot this piecewise function. Use Newton-Raphson method to find the x location of the maximum displacement with 3 significant figures of accuracy. Print the answer to the screen using appropriate formatting. mm 238.25x 238.25x 20 kips/ft 5' x³ - 238.25x 150 kip-ft 0≤x≤5 5 < x≤7 7 < x≤8 8 < x≤ 10 15 kips 2' 7/7/7/7
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