Piston Area: (Q2) A cylinder applies a force of 400 pounds in extension. If the pressure in the cylinder is 39 psi what is the area of the piston in square inches? Use πon your calculator Answer with two decimals. Do not write the unit.
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Piston Area: (Q2)
A cylinder applies a force of 400 pounds in extension. If the pressure in the cylinder is 39 psi what is the area of the piston in square inches?
Use πon your calculator
Answer with two decimals. Do not write the unit.
Step by step
Solved in 2 steps
- Please make sure answers are clear n easy to read. Please do it on white paper. Again make sure the answer is clear.The volume of a gas is increased, and the temperature is maintained consent. The original volume was 1200 mm3 and its pressure was 100 psi. What is the new pressure in psi, if the volume is increased to 2250 mm3? Use Two decimal places. Do not write the unit.Please do the last two questions (3 and 4)! Thank you in advance! A seesaw that weights 45lbs and its 5m long is balanced on the fulcrum in the center. 1- Two children are sitting on opposite sides of each other on the seesaw. One child weights 50lbs and is sitting 0.7m on the left end. Where should the other child sit in order to be balanced on the seesaw if they weigh 42lbs? 2- Now, a third child wants to sit on the seesaw and weighs 30lbs and is sitting 1.25m in front of them and is closer to the fulcrum on the right side. What are the CW and CCW moment of the seesaw now? What is the net moment and direction? 3- Then, a fourth child wants to play on the seesaw and is on the left side of the plank in order to bring the system to equilibrium. How much does the child weigh (Calculate the pounds of force needed in order for rebalance?) 4- Now the fourth child leaves the other three children sitting on the plank. If the three children are sitting in the same potions as they did in…
- Please do the last three questions (2, 3 and 4)! Thank you in advance! A seesaw that weights 45lbs and its 5m long is balanced on the fulcrum in the center. 1- Two children are sitting on opposite sides of each other on the seesaw. One child weights 50lbs and is sitting 0.7m on the left end. Where should the other child sit in order to be balanced on the seesaw if they weigh 42lbs? 2- Now, a third child wants to sit on the seesaw and weighs 30lbs and is sitting 1.25m in front of them and is closer to the fulcrum on the right side. What are the CW and CCW moment of the seesaw now? What is the net moment and direction? 3- Then, a fourth child wants to play on the seesaw and is on the left side of the plank in order to bring the system to equilibrium. How much does the child weigh (Calculate the pounds of force needed in order for rebalance?) 4- Now the fourth child leaves the other three children sitting on the plank. If the three children are sitting in the same potions as they did…Two vessels are connected to a differential manometer using mercury, the connecting tubing being filled with water. The higher pressure vessel is 1.5 m lower in elevation than the other. If carbon tetrachloride (SG = 1.59) were used instead of mercury, what woud be the manometer reading for the same pressure difference? Round your answer to 3 decimal places.Find the volume of the following: a. 5 cube b. 10 of 8 pipe
- Weight of Air: If you could collect the air in a square inch column of air starting at sea level going all the way to space, how much would it weigh? Answer with one decimal. Do not write the unit.The distance between two stations A and B is 100 kilometers and its equivalent distance onthe railway map measure 2.5 cm. What is the R.F? Draw a diagonal scale showing kilometersonly and indicate 473 kilometers on the scale.Directions: Show your complete solutions and box your final answer. Do not round off in between the solutions but round off your final answer to the nearest ten thousandths place(4 decimal places). 1.Find the volume of the fluid in cm3 with a mass of 0.31 kgm and density of 30 lbm/ft3.
- The wind chill (i.e. how cold it actually feels) is given by W(T,v) = 35.74 +0.6215T – 35.75v0.16 + 0.4275Tv0.16 degrees Fahrenheit when the actual air temperature is T degrees Fahrenheit and the wind speed is v miles per hour. Enter the function into your Y1 and verify that W(-5,15) = -25.80216395. Ploti Plot2 Plot3 1 -25.80216395 Y1835.74+0.6215T=5 T-35.75V0.16+0. V=151 4275TV6. 1Ği bound=(-1e99,1. Ýs= Use this function to answer questions 1 - 8.#16 please solve with all the needed units and proccesses.this is 100% correct, but please tell me how to solve this carefully.