The wind chill (i.e. how cold it actually feels) is given by W(T,v) = 35.74 + 0.6215T – 35.75vº.16 + 0.4275Tv0.16 degrees Fahrenheit when the actual air temperature is T degrees Fahrenheit and the wind speed is v miles per hour. Enter the function into your Y1 and verify that W(-5,15) = -25.80216395. Ploti Plot2 Plot3 V1B35.74+0.6215T=-5 T-35.75V 0.16+0. V=15cal ree 4275TV*6. I6i V1=0_ -25.80216395 bound=(-1E99, 1.
The wind chill (i.e. how cold it actually feels) is given by W(T,v) = 35.74 + 0.6215T – 35.75vº.16 + 0.4275Tv0.16 degrees Fahrenheit when the actual air temperature is T degrees Fahrenheit and the wind speed is v miles per hour. Enter the function into your Y1 and verify that W(-5,15) = -25.80216395. Ploti Plot2 Plot3 V1B35.74+0.6215T=-5 T-35.75V 0.16+0. V=15cal ree 4275TV*6. I6i V1=0_ -25.80216395 bound=(-1E99, 1.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![**Wind Chill Calculation and Verification**
The wind chill (i.e., how cold it actually feels) is given by the equation:
\[ W(T, v) = 35.74 + 0.6215T - 35.75v^{0.16} + 0.4275Tv^{0.16} \]
This calculates the apparent temperature in degrees Fahrenheit when the actual air temperature is \( T \) degrees Fahrenheit and the wind speed is \( v \) miles per hour.
To verify this, enter the function into your calculator's \( Y_1 \) and confirm that \( W(-5, 15) = -25.80216395 \).
**Graphical Explanation:**
- The first screen shows the function \( Y_1 \) entered into a calculator with the variables corresponding to the wind chill formula, indicating how to input the constants and variables \( T \) and \( v \).
- The second screen shows the calculator result for the specified input, confirming the output as \(-25.80216395\).
**Instruction:**
Use this function to answer questions 1 - 8.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ad87420-52d2-4e34-815e-eb9bcb5c95c0%2Fce543d60-f555-4b16-af7f-e2faf9163c15%2Fwqn0pqa_processed.png&w=3840&q=75)
Transcribed Image Text:**Wind Chill Calculation and Verification**
The wind chill (i.e., how cold it actually feels) is given by the equation:
\[ W(T, v) = 35.74 + 0.6215T - 35.75v^{0.16} + 0.4275Tv^{0.16} \]
This calculates the apparent temperature in degrees Fahrenheit when the actual air temperature is \( T \) degrees Fahrenheit and the wind speed is \( v \) miles per hour.
To verify this, enter the function into your calculator's \( Y_1 \) and confirm that \( W(-5, 15) = -25.80216395 \).
**Graphical Explanation:**
- The first screen shows the function \( Y_1 \) entered into a calculator with the variables corresponding to the wind chill formula, indicating how to input the constants and variables \( T \) and \( v \).
- The second screen shows the calculator result for the specified input, confirming the output as \(-25.80216395\).
**Instruction:**
Use this function to answer questions 1 - 8.
![**Question: Determining Wind Speed from Wind Chill**
On a cold day in Toronto, the temperature was 0 degrees Fahrenheit, and the wind chill was -15 degrees Fahrenheit. What was the wind speed? *Round your answer to three decimal places and give the units in the next question.*
[Answer Box]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ad87420-52d2-4e34-815e-eb9bcb5c95c0%2Fce543d60-f555-4b16-af7f-e2faf9163c15%2Fhtirwm_processed.png&w=3840&q=75)
Transcribed Image Text:**Question: Determining Wind Speed from Wind Chill**
On a cold day in Toronto, the temperature was 0 degrees Fahrenheit, and the wind chill was -15 degrees Fahrenheit. What was the wind speed? *Round your answer to three decimal places and give the units in the next question.*
[Answer Box]
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